Is the neon molecule Ne_2 possible? Why? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The electronic configuration of $Ne$ $(Z=10)$ is $1s^2 2s^2 2p^6$. For $Ne_2$ molecule,the total number of electrons is $20$. The molecular orbita

Vedclass · Accepted Answer

No,it is unstable due to zero bond order.

Vedclass · Answer

(B) The electronic configuration of $Ne$ $(Z=10)$ is $1s^2 2s^2 2p^6$. For $Ne_2$ molecule,the total number of electrons is $20$. The molecular orbital configuration is $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2, \sigma^* 2p_z^2$. Bond order = $\frac{1}{2} (N_b - N_a) = \frac{1}{2} (10 - 10) = 0$. Since the bond order is $0$,the $Ne_2$ molecule is unstable and does not exist.

Is the neon molecule $Ne_2$ possible? Why?

Similar Questions

Calculate the bond order for $H_2^+$,$He_2^+$,and $He_2^{2+}$.

The bond order and magnetic property of acetylide ion are same as that of $........$.

$KO_2$ exhibits paramagnetic behaviour. This is due to the paramagnetic nature of

The number of electrons present in bonding and antibonding orbitals in $O_2^{2-}$ is respectively

Assuming that Hund's rule is violated,the bond order and magnetic nature of the diatomic molecule $B_2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module