Calculate the bond order for H_2^+,He_2^+,and | vedclass

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Question

(A) The bond order is calculated using the formula: $Bond \ Order = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is t

Vedclass · Accepted Answer

$0.5, 0.5, 1$

Vedclass · Answer

(A) The bond order is calculated using the formula: $Bond \ Order = \frac{N_b - N_a}{2}$,where $N_b$ is the number of bonding electrons and $N_a$ is the number of antibonding electrons. SpeciesElectronic ConfigurationBond Order$H_2^+$$(\sigma 1s)^1$$(1-0)/2 = 0.5$$He_2^+$$(\sigma 1s)^2 (\sigma^* 1s)^1$$(2-1)/2 = 0.5$$He_2^{2+}$$(\sigma 1s)^2$$(2-0)/2 = 1$

Calculate the bond order for $H_2^+$,$He_2^+$,and $He_2^{2+}$.

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