Competitive Exam Reasoning · Series completion · Series completion
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Choose the correct alternative answer
$bca.....b....aabc....a...caa$
$acab$
$bcbb$
$cbab$
$ccab$
Solution
The series is$: bcaa/bcaa/bcaa/bcaa.$
Choose the correct alternative answer
$m....nm....n.....an.....a....ma.....$
$aamnan$
$ammanm$
$aammnn$
$amammn$
Solution
The series is$: man/man/man/man/man.$
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Study of the following arrangement carefully and answer the questions given below.
$Q,E ,* ,P,M ,8 ,R,A ,@ ,C ,9 ,U,H,W, \# ,J,Z, ,S, \beta, Y,N ,5 ,\$ ,G,I,T$
What should come in place of the question mark $(?)$ in the following series based on the above arrangement?
$QP@,MAH,@YZ,?$
$H\#Y$
$WZY$
$HJN$
$9\#S$
Solution
$Q \stackrel{+4}{\longrightarrow} M \stackrel{+4}{\longrightarrow} @ \stackrel{+4}{\longrightarrow} H$
$P \stackrel{+4}{\longrightarrow} A \stackrel{+4}{\longrightarrow} U \stackrel{+4}{\longrightarrow} J$
$@ \stackrel{+4}{\longrightarrow} H \stackrel{+4}{\longrightarrow} Z \stackrel{+4}{\longrightarrow} N$
Study of the following arrangement carefully and answer the questions given below.
$Q,E ,* ,P,M ,8 ,R,A ,@ ,C ,9 ,U,H,W, \# ,J,Z, ,S, \beta, Y,N ,5 ,\$ ,G,I,T$
Which of the following is eighth to the right of the thirteenth element from the left end of the arrangement?
$M$
$N$
$5$
$8$
Solution
$8th$ to the right of $13 th$ from the left means $21 st$ from left.
$21 st$ from left $\Rightarrow N$
Study of the following arrangement carefully and answer the questions given below.
$Q,E ,* ,P,M ,8 ,R,A ,@ ,C ,9 ,U,H,W, \# ,J,Z, ,S, \beta, Y,N ,5 ,\$ ,G,I,T$
Which of the following is exactly in the middle between the twelfth from the right and the seventh from the left end?
$3$
$\#$
$U$
$9$
Solution
$R,A ,@, C, \underline9 ,O,H,W ,\#$
Study of the following arrangement carefully and answer the questions given below.
$Q,E ,* ,P,M ,8 ,R,A ,@ ,C ,9 ,U,H,W, \# ,J,Z, ,S, \beta, Y,N ,5 ,\$ ,G,I,T$
If the first element in the above arrangement exchanges its position with the element in the $26 th$ position and the second with the one in the $25 th$ position and so on, which of the following will be in the tenth position from the left after rearrangement?
$Z$
$M$
$C$
$5$
Solution
There are $26$ elements. After rearrangement$, 13 th$ element from the right will become $13 th$ element from the left. Therefore$, 10 th$ from the left after rearrangement will be the $10 th$ element from the right in the original sequence.
$10 th$ from right $\Rightarrow Z$
These questions are based on the following arrangement. Study it carefully and answer the questions.
$J ,\star, R, 3, P,L ,2 ,\# ,I,N, 7, O,C, @ ,K, 5, D, =, M, \$, 6, B, > ,A ,Q ,4$
Four of the following five are alike in a certain way based on the positions of the elements in the arrangement and hence form a group. Which one does not belong to the group?
$23\#$
$OIC$
$KO5$
$B\$>$
Solution
$2 \stackrel{-3}{\longrightarrow} 3 \stackrel{+4}{\longrightarrow} \#$
$O \stackrel{-3}{\longrightarrow} 1 \stackrel{+4}{\longrightarrow} C$
$K \stackrel{-3}{\longrightarrow} O\stackrel{+4}{\longrightarrow} 5$
$\# \stackrel{-3}{\longrightarrow} P \stackrel{+4}{\longrightarrow} I$
$B \stackrel{-2}{\longrightarrow} \$ \stackrel{-3}{\longrightarrow}>$
Solution
These questions are based on the following arrangement. Study it carefully and answer the questions.
$J ,\star, R, 3, P,L ,2 ,\# ,I,N, 7, O,C, @ ,K, 5, D, =, M, \$, 6, B, > ,A ,Q ,4$
If the above arrangement is written in reverse order, which element will be eleventh to the left of sixteenth from the left?
$J$
$6$
$B$
$>$
Solution
$11th$ to the left of $16 th$ from left means $5 th$ from the left. But the sequence has been reversed. Therefore, required element will be $5 th$ from right in the original sequence.
$5th$ from right $\Rightarrow B$
These questions are based on the following arrangement. Study it carefully and answer the questions.
$J ,\star, R, 3, P,L ,2 ,\# ,I,N, 7, O,C, @ ,K, 5, D, =, M, \$, 6, B, > ,A ,Q ,4$
How many such numbers are there in the above arrangement which are not immediately followed by a symbol and also are immediately preceded by a consonant?
Nil
Two
Four
Three
Solution
Such combination are:
$R 3 P , N 7 O , K 5 D , Q 4$
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