Series completion Questions in English

(D) The given series is $8, 27, 125, 343, 1331$.
These numbers can be expressed as cubes of prime numbers:
$2^{3} = 8$
$3^{3} = 27$
$5^{3} = 125$
$7^{3} = 343$
$11^{3} = 1331$
Since all the terms in the series follow the pattern of cubes of consecutive prime numbers $(2, 3, 5, 7, 11)$,there is no wrong term in the series.

(D) The series follows a pattern where the numbers are alternately increased by $4$ and then multiplied by $2$ to obtain the next term.
Step $1$: $10 + 4 = 14$
Step $2$: $14 \times 2 = 28$
Step $3$: $28 + 4 = 32$
Step $4$: $32 \times 2 = 64$
Step $5$: $64 + 4 = 68$
Step $6$: $68 \times 2 = 136$
Comparing this with the given series,the last term is $132$,which is incorrect. It should be $136$.

(B) The given sequence is a combination of two alternating series:
Series $I$: $1, 5, 7, 11, 12$
Series $II$: $5, 9, 11, 15, 17$
Analyzing the pattern in both series:
For Series $I$: $1 (+4) = 5, 5 (+2) = 7, 7 (+4) = 11, 11 (+2) = 13$.
For Series $II$: $5 (+4) = 9, 9 (+2) = 11, 11 (+4) = 15, 15 (+2) = 17$.
The pattern in both series is $+4, +2, +4, +2$.
In Series $I$,the last term is $12$,which should be $13$ according to the pattern.
Therefore,$12$ is the wrong term.

(C) The given sequence is a combination of two series:
Series $I$: $11, 21, 32, 41, 51$
Series $II$: $2, 3, 4, 5, 6$
In Series $I$,the pattern is adding $10$ to the previous term ($11+10=21$,$21+10=31$,$31+10=41$,$41+10=51$).
Comparing this with the given series,the term $32$ is incorrect and should be $31$.

(C) The given series is a combination of two alternating series:
Series $I$: $11, 20, 40, 74$
Series $II$: $5, 12, 26, 54$
Let's analyze the pattern in Series $I$:
$11 + 9 = 20$
$20 + 18 = 38$ (instead of $40$)
$38 + 36 = 74$
Let's analyze the pattern in Series $II$:
$5 \times 2 + 2 = 12$
$12 \times 2 + 2 = 26$
$26 \times 2 + 2 = 54$
Since the pattern in Series $I$ requires the term to be $38$ instead of $40$,the wrong term in the series is $40$.

(D) The given series follows the pattern of the product of two consecutive integers:
$56 = 7 \times 8$
$72 = 8 \times 9$
$90 = 9 \times 10$
$110 = 10 \times 11$
$132 = 11 \times 12$
Following this pattern,the next term should be $12 \times 13 = 156$.
However,the given term is $150$.
Therefore,$150$ is the wrong term in the series.

(C) Let us analyze the differences between consecutive terms in the series:
$13 - 8 = 5$
$21 - 13 = 8$
$32 - 21 = 11$
$47 - 32 = 15$
$63 - 47 = 16$
$83 - 63 = 20$
The pattern of differences is $5, 8, 11, 14, 17, 20$ (increasing by $3$ each time).
Following this pattern:
$8 + 5 = 13$
$13 + 8 = 21$
$21 + 11 = 32$
$32 + 14 = 46$ (instead of $47$)
$46 + 17 = 63$
$63 + 20 = 83$
Therefore,the wrong term is $47$.

(C) The series follows an alternating pattern of addition and subtraction with decreasing values:
$89 - 11 = 78$
$78 + 9 = 87$
$87 - 7 = 80$
$80 + 5 = 85$
$85 - 3 = 82$
$82 + 1 = 83$
Comparing this with the given series $89, 78, 86, 80, 85, 82, 83$,we see that the third term is $86$ instead of $87$.
Therefore,$86$ is the wrong term.

(A) The given series is $25, 36, 49, 81, 121, 169, 225$.
These numbers can be written as squares of integers:
$5^{2} = 25$
$6^{2} = 36$
$7^{2} = 49$
$9^{2} = 81$
$11^{2} = 121$
$13^{2} = 169$
$15^{2} = 225$
Observing the pattern of the bases: $5, 6, 7, 9, 11, 13, 15$. The sequence of bases should be consecutive odd numbers starting from $5$ (i.e.,$5, 7, 9, 11, 13, 15$).
Since $6^{2} = 36$ is present instead of $7^{2} = 49$ (or rather,$6$ is not an odd number),$36$ is the wrong term in this series.

(D) The given series follows the pattern $n^{2} + 1$,where $n$ represents the position of the term starting from $n = 1$.
For $n = 1: 1^{2} + 1 = 2$
For $n = 2: 2^{2} + 1 = 5$
For $n = 3: 3^{2} + 1 = 10$
For $n = 4: 4^{2} + 1 = 17$
For $n = 5: 5^{2} + 1 = 26$
For $n = 6: 6^{2} + 1 = 37$
For $n = 7: 7^{2} + 1 = 50$
For $n = 8: 8^{2} + 1 = 65$
In the given series,the last term is $64$,but according to the pattern,it should be $65$. Therefore,$64$ is the wrong term.

(B) The given series is $1, 5, 9, 16, 25, 37, 49$.
Let us analyze the differences between consecutive terms:
$5 - 1 = 4$
$9 - 5 = 4$
$16 - 9 = 7$
$25 - 16 = 9$
$37 - 25 = 12$
$49 - 37 = 12$
This does not show a clear pattern. Let us look at the squares of odd numbers:
$1^2 = 1$
$3^2 = 9$
$5^2 = 25$
$7^2 = 49$
These are the $1st, 3rd, 5th,$ and $7th$ terms.
Now look at the even-positioned terms: $5, 16, 37$.
$2^2 + 1 = 5$
$4^2 + 1 = 17$
$6^2 + 1 = 37$
In the given series,the $4th$ term is $16$,but it should be $17$ to follow the pattern $(n^2 + 1)$ for even positions. Therefore,$16$ is the wrong term.

(D) The pattern of the series is that each term is the product of the two preceding terms.
$2 \times 5 = 10$
$5 \times 10 = 50$
$10 \times 50 = 500$
$50 \times 500 = 25000$
Therefore,the term $5000$ is incorrect and should be replaced by $25000$.

(C) Analyze the pattern of division in the series:
$46080 \div 12 = 3840$
$3840 \div 10 = 384$
$384 \div 8 = 48$
$48 \div 6 = 8$
$8 \div 4 = 2$
$2 \div 2 = 1$
Comparing this with the given series $46080, 3840, 384, 48, 24, 2, 1$,we see that the term $24$ is incorrect. It should be $8$.

(C) Let us analyze the pattern of the differences between consecutive terms:
$105 - 85 = 20$
$85 - 60 = 25$
$60 - 30 = 30$
$30 - 0 = 30$
$0 - (-45) = 45$
$-45 - (-90) = 45$
The pattern of differences should be a decreasing sequence of multiples of $5$,specifically: $20, 25, 30, 35, 40, 45$.
Applying this pattern starting from $30$:
$30 - 35 = -5$
$-5 - 40 = -45$
$-45 - 45 = -90$
Since the term $0$ does not fit the pattern (it should be $-5$),$0$ is the wrong term.

(C) Let us analyze the differences between consecutive terms in the series:
$325 - 259 = 66$
$259 - 202 = 57$
$202 - 160 = 42$
$160 - 127 = 33$
$127 - 105 = 22$
$105 - 94 = 11$
The pattern of differences should be multiples of $11$ in descending order: $66, 55, 44, 33, 22, 11$.
If we replace $202$ with $204$,the differences become:
$325 - 259 = 66$
$259 - 204 = 55$
$204 - 160 = 44$
$160 - 127 = 33$
$127 - 105 = 22$
$105 - 94 = 11$
Thus,the wrong term is $202$.

(D) The pattern of the series is as follows:
$125 + 1 = 126$
$126 - 2 = 124$
$124 + 3 = 127$
$127 - 4 = 123$
$123 + 5 = 128$
Comparing this with the given series,the last term is $129$ instead of $128$.
Therefore,$129$ is the wrong term.

(B) The pattern of the series is as follows:
$1st$ term: $3$
$2nd$ term: $(3 + 1) \times 1 = 4$
$3rd$ term: $(4 + 1) \times 2 = 10$
$4th$ term: $(10 + 1) \times 3 = 33$ (instead of $32$)
$5th$ term: $(33 + 1) \times 4 = 136$
$6th$ term: $(136 + 1) \times 5 = 685$
$7th$ term: $(685 + 1) \times 6 = 4116$
Therefore,the wrong term in the series is $32$,which should be replaced by $33$.

(C) The series follows a pattern of groups of three: $(n, n^2, n^3)$.
For $n = 3$: The terms are $3, 3^2 = 9, 3^3 = 27$.
For $n = 4$: The terms are $4, 4^2 = 16, 4^3 = 64$.
For $n = 5$: The terms are $5, 5^2 = 25, 5^3 = 125$.
Comparing this with the given series $3, 10, 27, 4, 16, 64, 5, 25, 125$,we see that $10$ is incorrect and should be $9$.

(A) The given series follows the pattern $n^{3} - 3$ for $n = 2, 3, 4, 5, 6, 7, 8$.
Calculating the terms:
For $n = 2: 2^{3} - 3 = 8 - 3 = 5$
For $n = 3: 3^{3} - 3 = 27 - 3 = 24$
For $n = 4: 4^{3} - 3 = 64 - 3 = 61$
For $n = 5: 5^{3} - 3 = 125 - 3 = 122$
For $n = 6: 6^{3} - 3 = 216 - 3 = 213$
For $n = 7: 7^{3} - 3 = 343 - 3 = 340$
For $n = 8: 8^{3} - 3 = 512 - 3 = 509$
Comparing this with the given series $5, 27, 61, 122, 213, 340, 509$,we see that $27$ is the wrong term,as it should be $24$.

(B) Let us analyze the differences between consecutive terms in the series:
$22 - 16 = 6$
$30 - 22 = 8$
$45 - 30 = 15$
$52 - 45 = 7$
$66 - 52 = 14$
The pattern of differences should be consecutive even numbers: $6, 8, 10, 12, 14$.
If we follow this pattern starting from $30$:
$30 + 10 = 40$
$40 + 12 = 52$
$52 + 14 = 66$
Thus,the term $45$ is incorrect and should be $40$.

(B) Let us analyze the pattern of the series: $1, 2, 5, 11, 10, 17, 28$.
If we look at the differences between consecutive terms:
$2 - 1 = 1$
$5 - 2 = 3$
$11 - 5 = 6$
$10 - 11 = -1$
This does not follow a clear pattern.
Let us re-examine the series by splitting it into two alternating series:
Series $1$: $1, 5, 10, 28$
Series $2$: $2, 11, 17$
This also does not seem to follow a simple arithmetic progression.
Let us check the pattern of adding consecutive odd numbers:
$1 + 1 = 2$
$2 + 3 = 5$
$5 + 6 = 11$ (Here,if we add $5$ instead of $6$,we get $10$)
$11 + 6 = 17$
$17 + 9 = 26$
Actually,the series follows the pattern of adding consecutive odd numbers starting from $1$ $(+1, +3, +5, +7, +9)$:
$1 + 1 = 2$
$2 + 3 = 5$
$5 + 5 = 10$
$10 + 7 = 17$
$17 + 9 = 26$
Comparing this with the given series $1, 2, 5, 11, 10, 17, 28$,we see that $11$ is incorrect and should be $10$,and $28$ is incorrect and should be $26$. However,looking at the options provided,the term $28$ is clearly the one that breaks the sequence $1, 2, 5, 10, 17, 26$. Thus,$28$ is the wrong term.

(B) Analyze the differences between consecutive terms:
$5 - 1 = 4$
$11 - 5 = 6$
$19 - 11 = 8$
$29 - 19 = 10$
The pattern of differences is an arithmetic progression: $+4, +6, +8, +10, \dots$
Following this pattern,the next difference should be $+12$.
Therefore,the next term should be $29 + 12 = 41$.
To verify,the difference after $41$ should be $+14$,and $41 + 14 = 55$,which matches the final term in the series.
Thus,$41$ is the missing term.

(A) The given series is $2, 3, 5, 8, 13, 34$.
Observing the pattern,each term is the sum of the two preceding terms (Fibonacci-like sequence):
$2 + 3 = 5$
$3 + 5 = 8$
$5 + 8 = 13$
$8 + 13 = 21$
$13 + 21 = 34$
Therefore,the missing term in the series is $21$.

(D) The pattern of the series is based on the difference between consecutive terms:
$3 - 0 = 3$
$8 - 3 = 5$
$15 - 8 = 7$
$24 - 15 = 9$
The differences are consecutive odd numbers: $3, 5, 7, 9, ...$
Following this pattern,the next difference should be $11$.
Therefore,the next term should be $24 + 11 = 35$.
Since the given series has $33$ instead of $35$,$33$ is the wrong term.

(C) The differences between consecutive terms are:
$5 - 1 = 4 = 2^{2}$
$14 - 5 = 9 = 3^{2}$
$30 - 14 = 16 = 4^{2}$
$55 - 30 = 25 = 5^{2}$
The next difference should be $6^{2} = 36$.
Therefore,the next term should be $55 + 36 = 91$.
Since the given series has $93$ instead of $91$,$93$ is the wrong term.

(C) Let us analyze the series: $4, 6, 40, 2, 16, 14, 22$.
This series appears to be a combination of two alternating series:
Series $1$: $4, 40, 16, 22$ (No clear pattern).
Let us re-examine the series $4, 6, 40, 2, 16, 14, 22$ by looking at the differences:
$6 - 4 = 2$
$40 - 6 = 34$
$2 - 40 = -38$
This does not show a simple arithmetic progression.
Let us check the pattern: $4 (+2) = 6$,$6 (+34) = 40$,$40 (-38) = 2$,$2 (+14) = 16$,$16 (-2) = 14$,$14 (+8) = 22$.
Actually,the series is $4, 6, 8, 10, 12, 14, 16, 18, 20, 22$ with some numbers missing or replaced.
Given the sequence $4, 6, 40, (2), 16, (14), 22$,if we assume the pattern is $+2$ increment:
$4, 6, 8, 10, 12, 14, 16, 18, 20, 22$.
The terms in the brackets are $(2)$ and $(14)$.
Comparing the given series $4, 6, 40, 2, 16, 14, 22$ to the expected sequence,the first bracketed term $(2)$ is wrong (should be $8$) and the second bracketed term $(14)$ is correct as it fits the sequence.
Therefore,the first term is wrong and the second is right.

(A) The given sequence is $3, 10, 29, 66, 127, 218$.
Observe the pattern:
$1^{3} + 2 = 1 + 2 = 3$
$2^{3} + 2 = 8 + 2 = 10$
$3^{3} + 2 = 27 + 2 = 29$
$4^{3} + 2 = 64 + 2 = 66$
$5^{3} + 2 = 125 + 2 = 127$
$6^{3} + 2 = 216 + 2 = 218$
Since both $66$ and $127$ follow the pattern $n^{3} + 2$,both bracketed terms are correct.

(B) Analyze the pattern of the series: $2, 3, 6, 11, 18, 30, 38$.
The differences between consecutive terms are:
$3 - 2 = 1$
$6 - 3 = 3$
$11 - 6 = 5$
$18 - 11 = 7$
$30 - 18 = 12$
$38 - 30 = 8$
The pattern of differences should be consecutive odd numbers: $1, 3, 5, 7, 9, 11$.
Checking the terms:
$2 + 1 = 3$
$3 + 3 = 6$ (Correct)
$6 + 5 = 11$
$11 + 7 = 18$
$18 + 9 = 27$ (The term $30$ is wrong,it should be $27$)
$27 + 11 = 38$ (Correct)
Thus,the first bracketed term $(6)$ is correct,and the second bracketed term $(30)$ is wrong.

(D) Let us analyze the pattern of the series: $2, 5, 12, 25, 41, 61$.
The differences between consecutive terms are:
$5 - 2 = 3$
$12 - 5 = 7$
$25 - 12 = 13$
$41 - 25 = 16$
$61 - 41 = 20$
This does not show a clear pattern. Let us re-examine the series $2, 5, 12, 25, 41, 61$ by checking the second-order differences:
$5 - 2 = 3$
$12 - 5 = 7$
$25 - 12 = 13$
$41 - 25 = 16$
$61 - 41 = 20$
Actually,the series follows the pattern of adding consecutive multiples of $4$ or specific increments. Let's test the sequence $2, 5, 10, 17, 26, 37...$ (not matching).
Let's look at the differences again: $5-2=3, 12-5=7, 25-12=13, 41-25=16, 61-41=20$.
If the series was $2, 6, 12, 20, 30, 42$ (pattern $n^2+n$),then $2$ and $12$ are wrong.
Given the options provided in the prompt,the intended logic is: The sequence is $2, 5, 10, 17, 26, 37$ (where $n^2+1$).
Comparing $2, 5, 12, 25, 41, 61$ with $2, 5, 10, 17, 26, 37$,both bracketed terms $(12)$ and the initial term $2$ are incorrect based on standard series logic.

(A) Let us analyze the pattern of the given series: $4, 7, 10, 13, 16, 19$ and $7, 10, 13, 16, 19$ are not the primary focus,but rather the sequence of differences.
The series is: $4, 7, 9, 10, 13, 15, 16, 19$.
Let's check the differences between consecutive terms:
$7 - 4 = 3$
$9 - 7 = 2$
$10 - 9 = 1$
$13 - 10 = 3$
$15 - 13 = 2$
$16 - 15 = 1$
$19 - 16 = 3$
The pattern of differences is $+3, +2, +1, +3, +2, +1, +3$.
Since the pattern holds true for all terms,both bracketed terms $9$ and $16$ are correct.

(D) The given series is $Z, X, V, T, R, (...), (...)$.
Observing the pattern,each letter is obtained by skipping one letter in the reverse alphabetical order:
$Z (-2) = X$
$X (-2) = V$
$V (-2) = T$
$T (-2) = R$
Following this pattern,the next terms are:
$R (-2) = P$
$P (-2) = N$
Therefore,the missing terms are $P$ and $N$.

(D) Let us analyze the pattern of the sequence: $nd, iy, dt, yo, tj$.
$1$. First letter pattern:
$n \xrightarrow{-5} i \xrightarrow{-5} d \xrightarrow{-5} y \xrightarrow{-5} t \xrightarrow{-5} o$.
$2$. Second letter pattern:
$d \xrightarrow{+5} i \xrightarrow{+11} t \xrightarrow{+5} y \xrightarrow{+11} j \xrightarrow{+5} o$.
Wait,let's re-evaluate the pattern:
$n(14) \to i(9) \to d(4) \to y(25) \to t(20) \to o(15)$. (Subtract $5$ each time).
$d(4) \to y(25) \to t(20) \to o(15) \to j(10) \to e(5)$. (Subtract $5$ each time).
Thus,the next term is $oe$.

(C) Let us analyze the pattern of the letters in each term:
$1$. The first letters are $B, C, D, ...$ which follow a pattern of $+1$ step forward. The next letter after $D$ is $E$.
$2$. The second letters are $D, F, H, ...$ which follow a pattern of $+2$ steps forward. The next letter after $H$ is $J$.
$3$. The third letters are $F, I, L, ...$ which follow a pattern of $+3$ steps forward. The next letter after $L$ is $O$.
Therefore,the next term in the series is $EJO$.

(A) The series follows a pattern for each letter position:
$1$. First letter: $Y \xrightarrow{-2} W \xrightarrow{-2} U \xrightarrow{-2} S \xrightarrow{-2} Q$.
$2$. Second letter: $E \xrightarrow{+1} F \xrightarrow{+2} H \xrightarrow{+3} K \xrightarrow{+4} O$.
$3$. Third letter: $B \xrightarrow{+2} D \xrightarrow{+3} G \xrightarrow{+2} I \xrightarrow{+3} L$.
Thus,the next term is $QOL$.

(A) The pattern for the series is as follows:
$1$. First letter: $A (+3) = D, D (+4) = H, H (+5) = M, M (+6) = S, S (+7) = Z$.
$2$. Second letter: $B (+5) = G, G (+6) = M, M (+7) = T, T (+8) = B, B (+9) = K$.
$3$. Third letter: $D (+7) = K, K (+8) = S, S (+9) = B, B (+10) = L, L (+11) = W$.
Thus,the missing term is $ZKW$.

(C) The series consists of three parts: letters at the beginning,numbers in the middle,and letters at the end.
$1$. First letters: $P, R, T, V, \dots$ follow a pattern of skipping one letter ($+2$ in alphabetical position). The next letter after $V$ is $X$.
$2$. Numbers: $3, 5, 8, 12, \dots$ follow the pattern of adding consecutive integers: $3+2=5, 5+3=8, 8+4=12$. The next number is $12+5=17$.
$3$. Last letters: $C, F, I, L, \dots$ follow a pattern of skipping two letters ($+3$ in alphabetical position). The next letter after $L$ is $O$.
Combining these,the next term is $X 17 O$.

(A) The given series is $U, O, I, ?, A$.
These are the English vowels $A, E, I, O, U$ arranged in reverse order.
The sequence is $U, O, I, E, A$.
Therefore,the missing term is $E$.

(D) The given series is $Y, W, U, S, Q, ?, ?$.
Observing the pattern,each letter is obtained by skipping one letter in the reverse alphabetical order:
$Y (-2) = W$
$W (-2) = U$
$U (-2) = S$
$S (-2) = Q$
Following this pattern:
$Q (-2) = O$
$O (-2) = M$
Therefore,the missing terms are $O$ and $M$.

(A) The positions of the letters in the English alphabet are:
$A = 1, B = 2, D = 4, G = 7$.
The pattern of the differences between consecutive terms is:
$B - A = 2 - 1 = 1$
$D - B = 4 - 2 = 2$
$G - D = 7 - 4 = 3$
Following this pattern,the next difference should be $4$.
Therefore,the next term is $7 + 4 = 11$.
The $11^{th}$ letter in the English alphabet is $K$.

(D) Let us analyze the positions of the letters in the English alphabet:
$Z = 26$
$U = 21$ (Difference: $26 - 21 = 5$)
$Q = 17$ (Difference: $21 - 17 = 4$)
Following the pattern of decreasing the difference by $1$ each time,the next difference should be $3$.
So,the next term should be $17 - 3 = 14$,which corresponds to the letter $N$.
To verify,the next difference should be $2$: $14 - 2 = 12$,which corresponds to the letter $L$.
Since $L$ is the last term in the series,the missing term is $N$.

(A) The pattern of the series is as follows:
$A (+2) = C$
$C (+3) = F$
$F (+2) = H$
$H (+3) = K$
$K (+2) = M$
Following this alternating pattern of adding $2$ and $3$ to the position of the letters in the alphabet,the missing term is $K$.

(A) The series follows a pattern of three interleaved sequences.
$1$. The first,fourth,and seventh terms are $A, B, C$. Following this pattern,the tenth term should be $D$.
$2$. The second and third terms are $Z, X$ (reverse alphabetical order with a gap of one letter). The fifth and sixth terms are $V, T$ (following the same pattern). The eighth and ninth terms are $R, ?$. Following the pattern,the letter before $R$ skipping one letter is $P$.
Thus,the missing terms are $P$ and $D$.

(A) Let us analyze the positions of the letters in the English alphabet: $R(18), M(13), F(6), D(4)$.
The pattern of the differences between consecutive letters is as follows:
$R - M = 18 - 13 = 5$ ($4$ letters skipped: $N, O, P, Q$)
$M - ? = 4$ ($3$ letters skipped: $I, J, K, L$ - wait,let us re-evaluate).
Looking at the sequence: $R(18) \xrightarrow{-5} M(13) \xrightarrow{-4} I(9) \xrightarrow{-3} F(6) \xrightarrow{-2} D(4) \xrightarrow{-1} C(3)$.
The missing terms are $I$ and $C$.

(A) The given sequence consists of two alternating series:
Series $1$: $Z, X, V, T, ?$
This series follows a pattern of $-2$ in the alphabet: $Z \xrightarrow{-2} X \xrightarrow{-2} V \xrightarrow{-2} T \xrightarrow{-2} R$.
Series $2$: $L, J, H, F, ?$
This series also follows a pattern of $-2$ in the alphabet: $L \xrightarrow{-2} J \xrightarrow{-2} H \xrightarrow{-2} F \xrightarrow{-2} D$.
Therefore,the missing terms are $R$ and $D$.

(A) The given sequence consists of two alternating series:
$I$. $Z, W, T, Q, ?$
In this series,each letter is moved three steps backward to obtain the next term:
$Z - 3 = W$
$W - 3 = T$
$T - 3 = Q$
$Q - 3 = N$
$II$. $S, O, K, G$
In this series,each letter is moved four steps backward to obtain the next term:
$S - 4 = O$
$O - 4 = K$
$K - 4 = G$
$G - 4 = C$
Thus,the missing terms are $N$ and $C$.

(D) The series follows a pattern of alternating subtractions.
Starting from $W$ $(23)$,the sequence is:
$W (-1) = V$ $(22)$
$V (-2) = T$ $(20)$
$T (-1) = S$ $(19)$
$S (-2) = Q$ $(17)$
$Q (-1) = P$ $(16)$
$P (-2) = N$ $(14)$
$N (-1) = M$ $(13)$
Following this pattern,the next steps are $(-2)$ and $(-1)$:
$M (-2) = K$ $(11)$
$K (-1) = J$ $(10)$
Therefore,the missing terms are $K$ and $J$.

(D) Analyze the pattern of the series:
$1$. The series is divided into groups of three consecutive letters in reverse alphabetical order: $(Z, Y, X)$,$(U, T, S)$,$(P, O, N)$,$(K, ?, ?)$.
$2$. Between each group,two letters are skipped:
- From $X$ to $U$,letters $W$ and $V$ are skipped.
- From $S$ to $P$,letters $R$ and $Q$ are skipped.
- From $N$ to $K$,letters $M$ and $L$ are skipped.
$3$. Following this pattern,after $K$,the next two letters should be $J$ and $I$ in reverse order.
Therefore,the missing terms are $J$ and $I$.

(A) The series can be analyzed by dividing it into groups of three: $(b, e, d), (f, ?, h), (j, ?, l)$.
Looking at the first letters of each group: $b, f, j$. The pattern is $+4$ $(b xrightarrow{+4} f xrightarrow{+4} j)$.
Looking at the third letters of each group: $d, h, l$. The pattern is $+4$ $(d xrightarrow{+4} h xrightarrow{+4} l)$.
Within each group $(x, y, z)$,the relationship is: the first letter $x$ moves $3$ steps forward to get the second letter $y$ $(x xrightarrow{+3} y)$,and the second letter $y$ moves $1$ step backward to get the third letter $z$ $(y xrightarrow{-1} z)$.
Applying this to the second group $(f, ?, h)$: $f xrightarrow{+3} i$. Checking the third letter: $i xrightarrow{-1} h$. This matches.
Applying this to the third group $(j, ?, l)$: $j xrightarrow{+3} m$. Checking the third letter: $m xrightarrow{-1} l$. This matches.
Therefore,the missing terms are $i$ and $m$.

(D) Analyze the pattern of the series:
$1$. The first letters are $A, B, C, ...$,which follow the alphabetical order. The next letter should be $D$.
$2$. The second letters are $Z, Y, X, ...$,which follow the reverse alphabetical order. The next letter should be $W$.
$3$. Combining these,the missing term is $DW$.

(C) Analyze the pattern of the first letters: $A (+2) \rightarrow C (+3) \rightarrow F (+4) \rightarrow J$. The first letter of the next term is $J$.
Analyze the pattern of the second letters: $Z (-2) \rightarrow X (-3) \rightarrow U (-4) \rightarrow Q$. The second letter of the next term is $Q$.
Thus,the missing term is $JQ$.