Puzzle Test Questions in English

(C) The available roads are $X, Y, Z, 1, 2, 3$.
$1$. When there is a storm,$Y$ is blocked.
$2$. When there are floods,$X, 1,$ and $2$ are blocked.
$3$. When road $1$ is blocked,$Z$ is also blocked.
Given that both a storm and floods occur simultaneously:
- From the storm: $Y$ is blocked.
- From the floods: $X, 1,$ and $2$ are blocked.
- Since $1$ is blocked,$Z$ is also blocked (as per the condition).
- Roads blocked: $X, Y, Z, 1, 2$.
- The only remaining road is $3$.
Therefore,only road $3$ can be used.

(D) $1$. Let the six persons be arranged in a circle.
$2$. Given that $F$ is to the left of $D$.
$3$. $A$ is between $E$ and $D$,so the sequence is $E-A-D$.
$4$. $B$ is between $F$ and $C$,so the sequence is $F-B-C$.
$5$. Combining these,if we place them in a circle: $D-A-E-C-B-F$ (in clockwise order).
$6$. Checking the conditions:
- $B$ is between $F$ and $C$ (True).
- $A$ is between $E$ and $D$ (True).
- $F$ is to the left of $D$ (True).
$7$. Looking at the circular arrangement,the person between $A$ and $F$ is $D$ and $E$ is not the one,but looking at the sequence $D-A-E-C-B-F$,the person between $A$ and $F$ is $D$ or $E$ depending on the path. However,re-evaluating the circle: $D, A, E, C, B, F$. The person between $A$ and $F$ is $D$ and $E$ are adjacent to $A$. Wait,let's re-map: $D$ is at the top,$A$ is to its right,$E$ is to the right of $A$,$C$ is to the right of $E$,$B$ is to the right of $C$,$F$ is to the right of $B$.
$8$. The sequence is $D-A-E-C-B-F$.
$9$. Between $A$ and $F$ (going clockwise): $E, C, B$. Between $A$ and $F$ (going counter-clockwise): $D$.
$10$. Based on standard circular seating logic,the person between $A$ and $F$ is $D$.

(C) Let us analyze the information given for each friend:
$1$. $D$ is a boxer and studies Maths and Accounts.
$2$. $A$ and $B$ play football. Both football players study Maths. Since each friend studies two subjects,and we know $A$ and $B$ study Maths,we need to find their second subject. One football player also studies Physics. Since $D$ is already accounted for,one of the football players ($A$ or $B$) must study Physics.
$3$. We have four friends: $A, B, C, D$. The games are: Cricketer,Boxer,Football,Football. Since $A$ and $B$ play football and $D$ is a boxer,$C$ must be the cricketer.
$4$. The cricketer studies Chemistry and Biology. Therefore,$C$ is the cricketer.

(C) Let us analyze the information given for each friend:
$1$. $D$ is a boxer and studies Maths and Accounts.
$2$. $A$ and $B$ play football and study Maths. Since one football player also studies Physics,and they study two subjects each,we need to determine the second subject for $A$ and $B$.
$3$. There is a cricketer who studies Chemistry and Biology. This must be $C$ because $A, B, D$ are already accounted for with their games.
$4$. The problem asks who studies Accounts and plays football. We know $D$ studies Accounts,but $D$ is a boxer. The football players are $A$ and $B$. However,the information provided states that the boxer $(D)$ studies Maths and Accounts. There is no mention of a football player studying Accounts. Re-evaluating the logic: If $D$ is the only one studying Accounts,and $D$ is a boxer,then no one who plays football studies Accounts. However,looking at the options and the constraints,if the question implies a potential error in the premise or a specific assignment,we must re-read: 'The boxer studies Maths and Accounts.' This confirms $D$ is the only one studying Accounts. Therefore,no one plays football and studies Accounts. Given the structure of such puzzles,if this were a multiple-choice question where one must be selected,there might be a contradiction in the question statement. Assuming the question implies finding the person who fits the criteria based on the provided text,and since $D$ is the only one studying Accounts,the answer is none of the above,but based on typical test patterns,if $D$ is the only one with Accounts,the question might be flawed. However,if we must choose,$D$ is the only one associated with Accounts.

(A) $1$. Identify the friends and their attributes:
- $A$ and $B$ play football. Since there are four friends and each plays one game,$C$ and $D$ must play other games.
- $D$ is a boxer. The remaining game is cricket,so $C$ must be the cricketer.
- The cricketer $(C)$ studies Chemistry and Biology.
- The boxer $(D)$ studies Maths and Accounts.
- $A$ and $B$ play football and both study Maths.
- We are told one football player also studies Physics. Since $D$ (boxer) already studies Maths and Accounts,and $C$ (cricketer) studies Chemistry and Biology,the Physics student must be one of the football players ($A$ or $B$).
- The problem states 'One football player also studies Physics'. Since both $A$ and $B$ play football and study Maths,and no further distinction is provided between $A$ and $B$,the student of Physics is either $A$ or $B$.

(D) Let's analyze the information given for each friend:
$1$. $D$ is a boxer and studies Maths and Accounts.
$2$. $A$ and $B$ play football and study Maths. Since each friend studies two subjects,we need to find the second subject for $A$ and $B$. One football player studies Physics,so let's assign Physics to $A$. $B$ must study another subject. Since there are $4$ friends and each studies $2$ subjects,there are $8$ subject-slots total.
$3$. $C$ is the cricketer and studies Chemistry and Biology.
$4$. Games played: Cricket (by $C$),Football (by $A$ and $B$),Boxing (by $D$). Total games = $3$.
$5$. Subjects studied: Maths (by $A, B, D$),Accounts (by $D$),Physics (by $A$),Chemistry (by $C$),Biology (by $C$). The second subject for $B$ is not explicitly named,but the total unique subjects are Maths,Accounts,Physics,Chemistry,Biology. Total subjects = $5$.
Thus,there are $3$ games and $5$ subjects.

(A) Let us represent the height relationships using the greater than sign $(>)$:
$1$. Shekhar $>$ Kunal
$2$. Atul $>$ Pawan
$3$. Kunal $>$ Atul (Since Atul is not as tall as Kunal)
$4$. Prashant $>$ Shekhar
Combining these,we get: Prashant $>$ Shekhar $>$ Kunal $>$ Atul $>$ Pawan.
Therefore,the order from tallest to shortest is: Prashant,Shekhar,Kunal,Atul,Pawan.
The shortest person is Pawan.

(C) Given conditions:
$1$. Order: $V > P > Q$ (where $>$ means finishes ahead of).
$2$. Case $1$: $R$ is $1^{st}$ and $T$ is $7^{th}$.
$3$. Case $2$: $S$ is $1^{st}$ and ($U$ or $Q$) is $7^{th}$.
Given $V$ is $5^{th}$:
Since $V > P > Q$,$P$ and $Q$ must finish after $V$. Thus,$P$ and $Q$ must occupy positions $6$ and $7$ (in that order).
This implies $Q$ is $7^{th}$.
Now,check the cases:
Case $1$: If $R$ is $1^{st}$ and $T$ is $7^{th}$,this contradicts $Q$ being $7^{th}$. So,Case $1$ is impossible.
Case $2$: $S$ is $1^{st}$ and ($U$ or $Q$) is $7^{th}$. Since $Q$ is $7^{th}$,this condition is satisfied.
Positions:
$1^{st}: S$
$2^{nd}, 3^{rd}, 4^{th}: R, T, U$ (in any order)
$5^{th}: V$
$6^{th}: P$
$7^{th}: Q$
Looking at the options,$S$ finishing $1^{st}$ is the only statement that must be true.

(D) Let the upward journey sequence be $1, 2, 3, 4, 5$.
$D$ is the first stop in the downward journey,so $D$ is the $5^{th}$ stop in the upward journey.
$A$ and $E$ are not terminal stops,so they cannot be $1$ or $5$.
$C$ is not the middle stop ($3^{rd}$ position).
Let the upward sequence be $x_1, x_2, x_3, x_4, D$.
$C$ comes twice as many stops before $D$ as $B$ comes after $A$.
If $A$ is at $1$ and $B$ is at $2$,then $B$ is $1$ stop after $A$. So $C$ must be $2$ stops before $D$.
If $D$ is $5$,$2$ stops before $D$ is $3$. So $C = 3$,but $C$ cannot be the middle stop.
If $A$ is at $2$ and $B$ is at $4$,then $B$ is $2$ stops after $A$. So $C$ must be $4$ stops before $D$.
If $D$ is $5$,$4$ stops before $D$ is $1$. So $C = 1$.
Remaining stops $A, E, B$ are at $2, 3, 4$. Since $A=2, B=4$,then $E=3$.
Upward sequence: $C, A, E, B, D$.
Downward sequence is the reverse: $D, B, E, A, C$.
Checking the options,$D, E, A, C, B$ is $DEACB$.

(D) Let the six chairs be numbered $1$ to $6$ in a clockwise direction.
Since $C$ is opposite $D$,let $D$ be at position $1$ and $C$ be at position $4$.
$A$ is between $D$ and $F$. Since $D$ is at $1$,$A$ must be at $2$ and $F$ must be at $3$ (or vice versa,but $A$ must be adjacent to $D$).
Given $D$ and $E$ are not neighbours,$E$ cannot be at $2$ or $6$. Since $2$ is occupied by $A$,$E$ must be at $5$.
Now,the remaining position $6$ must be occupied by $B$.
The arrangement is: $1: D, 2: A, 3: F, 4: C, 5: E, 6: B$.
Checking the pairs:
$A$ and $B$ are not neighbours ($2$ and $6$).
$A$ and $C$ are not neighbours ($2$ and $4$).
$B$ and $F$ are not neighbours ($6$ and $3$).
$C$ and $E$ are neighbours ($4$ and $5$).
Thus,the pair $C$ and $E$ must be sitting on neighbouring chairs.

(C) $1$. Identify the gender and status: $A$ and $D$ are ladies,unmarried,and not professors. $E$ is a husband,so $E$ is male. $B$ is the brother of $C$,so $B$ is male.
$2$. Identify the married couple: Since $E$ is the husband and there is one married couple,his wife must be one of the ladies ($A, C,$ or $D$). However,$A$ and $D$ are unmarried. Thus,$C$ must be the wife of $E$.
$3$. Determine the professors: There are three professors (Philosophy,Psychology,Economics). Since $A, D,$ and $C$ (the wife) are not professors (as $A$ and $D$ have no specialization and $C$ is the wife),the professors must be $B, E,$ and one other person. Wait,let's re-evaluate: $A, D$ are not professors. $B$ is not a psychologist or economist,so $B$ must be the Professor of Philosophy. $E$ is the husband,and $C$ is the wife. Since $B$ is the Professor of Philosophy,the remaining professors are Psychology and Economics. $C$ is not a professor. Therefore,$E$ must be one of the professors. Since $B$ is the Professor of Philosophy,and $B$ is not a psychologist or economist,$B$ is the Professor of Philosophy. Given $C$ is not a professor,and $A, D$ are not professors,the professors are $B, E,$ and one other. Actually,the group has $5$ people: $A, B, C, D, E$. If $A, D$ are not professors and $C$ is not a professor,then $B$ and $E$ are professors. But there are $3$ professors. Let's re-read: $A, D$ are ladies with no specialization. $B$ is not a psychologist or economist. $B$ is the Professor of Philosophy. $E$ is the husband. If $C$ is the wife,$C$ could be a professor. Since $B$ is Philosophy,and $B$ is not a psychologist or economist,$B$ is Philosophy. $C$ is the Professor of Psychology.

(B) $1$. Identify the gender of each person: $A$ and $D$ are ladies. Since there are $5$ people and $A, D$ are women,the remaining $B, C, E$ must be men.
$2$. Verify the conditions: $E$ is a husband,so $E$ is a man. $B$ is the brother of $C$,so $B$ is a man. Since $A$ and $D$ are unmarried ladies,the married couple must involve $E$ and one of the other members. Since $A$ and $D$ are unmarried,$C$ must be the wife of $E$. Thus,$C$ is a lady.
$3$. Re-evaluating the gender: $A$ (female),$D$ (female),$C$ (female). Therefore,the men in the group are $B$ and $E$.
$4$. Conclusion: The group of men is ${B, E}$.

(B) $1$. Identify the gender and status: $A$ and $D$ are unmarried ladies. $E$ is a husband,so $E$ is male. Since there is a married couple,$E$ must be married to one of the remaining persons ($B$ or $C$).
$2$. Analyze the professions: There are three professors (Philosophy,Psychology,Economics). $A$ and $D$ are not professors. Thus,$B, C,$ and $E$ must be the professors.
$3$. Analyze $B$: $B$ is not a psychologist and not an economist. Therefore,$B$ must be the Professor of Philosophy.
$4$. Analyze $C$: $B$ is the brother of $C$. Since $B$ is the Professor of Philosophy,$C$ must be one of the other professors (Psychology or Economics).
$5$. Conclusion: Since $B$ is the only one left who can be the Professor of Philosophy,the answer is $B$.

(A) $1$. Identify the gender and roles: $A$ and $D$ are unmarried ladies with no specialization. Since they are unmarried,they cannot be the wife of $E$.
$2$. The group consists of $A, B, C, D, E$. Since $A$ and $D$ are unmarried,the wife of $E$ must be $B$ or $C$.
$3$. $B$ is the brother of $C$,so $B$ is male. Therefore,$B$ cannot be the wife of $E$.
$4$. This leaves $C$ as the only remaining candidate to be the wife of $E$.
$5$. Since $E$ is the husband and $C$ is the wife,$C$ must be the Professor of Psychology (as $B$ is not a psychologist or economist,and $A, D$ are not professors).

(D) $1$. Identify the gender and status: $A$ and $D$ are unmarried ladies. Since $E$ is the husband in a married couple,the wife must be either $B$ or $C$. Since $B$ is the brother of $C$,$B$ is male. Thus,$C$ must be the wife of $E$.
$2$. Identify the professions: There are three professors (Philosophy,Psychology,Economics). $A$ and $D$ are not professors. Therefore,$B, C,$ and $E$ must be the professors.
$3$. Analyze constraints: $B$ is not a psychologist or an economist. Therefore,$B$ must be the Professor of Philosophy.
$4$. Analyze remaining: $C$ and $E$ are the Professor of Psychology and the Professor of Economics. Since $C$ is the wife and $E$ is the husband,and we know $B$ is the brother of $C$,we look at the remaining roles. Given $B$ is the Professor of Philosophy,and $C$ is not specified as the economist,we evaluate the remaining options. Since $B$ is the Professor of Philosophy,and $C$ and $E$ share the remaining two roles,and $C$ is female,and no lady is an economist,$C$ cannot be the Professor of Economics. Therefore,$E$ must be the Professor of Economics.