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Profit and Loss Questions in English
Competitive Exam Quantitative Aptitude · Profit and Loss · Profit and Loss
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DifficultMCQ
Meenal purchased a car for $Rs. 2,50,000$ and sold it for $Rs. 3,48,000$. What is the percent profit she made on the car?
A
$40$
B
$39.2$
C
$38.4$
D
$38$
Solution
(B) Cost Price $(CP)$ = $Rs. 2,50,000$
Selling Price $(SP)$ = $Rs. 3,48,000$
Profit = $SP - CP = 3,48,000 - 2,50,000 = Rs. 98,000$
Profit Percentage = $\left( \frac{\text{Profit}}{CP} \right) \times 100$
Profit Percentage = $\left( \frac{98,000}{2,50,000} \right) \times 100 = \frac{98}{250} \times 100 = \frac{98}{2.5} = 39.2 \%$
Selling Price $(SP)$ = $Rs. 3,48,000$
Profit = $SP - CP = 3,48,000 - 2,50,000 = Rs. 98,000$
Profit Percentage = $\left( \frac{\text{Profit}}{CP} \right) \times 100$
Profit Percentage = $\left( \frac{98,000}{2,50,000} \right) \times 100 = \frac{98}{250} \times 100 = \frac{98}{2.5} = 39.2 \%$
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View Solution452
DifficultMCQ
$A$ shopkeeper bought $30 \text{ kg}$ of wheat at the rate of $₹ 45$ per $\text{kg}$. He sold $40\%$ of the total quantity at the rate of $₹ 50$ per $\text{kg}$. Approximately,at what price per $\text{kg}$ should he sell the remaining quantity to make $25\%$ overall profit? (in $₹$)
A
$54$
B
$52$
C
$50$
D
$60$
Solution
(D) Total Cost Price $(C.P.)$ of wheat $= 30 \times 45 = ₹ 1350$.
To make an overall profit of $25\%$,the total Selling Price $(S.P.)$ should be $= 1350 \times \frac{125}{100} = 1350 \times 1.25 = ₹ 1687.5$.
Quantity sold first $= 40\% \text{ of } 30 \text{ kg} = 12 \text{ kg}$.
$S.P.$ of $12 \text{ kg} = 12 \times 50 = ₹ 600$.
Remaining quantity $= 30 - 12 = 18 \text{ kg}$.
Required $S.P.$ for the remaining $18 \text{ kg} = 1687.5 - 600 = ₹ 1087.5$.
Price per $\text{kg}$ for the remaining quantity $= \frac{1087.5}{18} \approx ₹ 60.42$.
Rounding to the nearest given option,the answer is $₹ 60$.
To make an overall profit of $25\%$,the total Selling Price $(S.P.)$ should be $= 1350 \times \frac{125}{100} = 1350 \times 1.25 = ₹ 1687.5$.
Quantity sold first $= 40\% \text{ of } 30 \text{ kg} = 12 \text{ kg}$.
$S.P.$ of $12 \text{ kg} = 12 \times 50 = ₹ 600$.
Remaining quantity $= 30 - 12 = 18 \text{ kg}$.
Required $S.P.$ for the remaining $18 \text{ kg} = 1687.5 - 600 = ₹ 1087.5$.
Price per $\text{kg}$ for the remaining quantity $= \frac{1087.5}{18} \approx ₹ 60.42$.
Rounding to the nearest given option,the answer is $₹ 60$.
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