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Pattern of Biodiversity Questions in English

Class 12 Biology · Biodiversity and Conservation · Pattern of Biodiversity

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Showing 8 of 58 questions in English

51
EasyMCQ
The variety of frugivorous organisms is greater in tropical rain forests compared to temperate regions because of:
A
warmer temperature
B
higher annual rainfall
C
availability of fruit throughout the year
D
constant climate conditions

Solution

(C) Tropical rain forests are characterized by a lack of distinct seasonal changes and a stable,warm climate. This environment allows for the continuous growth and production of fruits throughout the year. In contrast,temperate regions experience distinct seasons,which limit the period during which fruits are available. Therefore,the constant availability of food resources (fruits) in tropical rain forests supports a higher diversity of frugivorous organisms.
52
EasyMCQ
Species diversity is higher at lower altitudes than at higher altitudes because at higher altitudes:
A
there is no change in climatic conditions and no seasonal variations.
B
there is change in climatic conditions and drastic seasonal variations.
C
there is intense sunlight and warmer temperature.
D
there is higher annual rainfall and more migration.

Solution

(B) Species diversity generally decreases as we move from the equator towards the poles or from lower altitudes to higher altitudes. This is primarily due to the harsh environmental conditions found at higher altitudes. At higher altitudes,the climatic conditions are unstable,and there are drastic seasonal variations,which make it difficult for many species to survive and thrive. In contrast,lower altitudes provide more stable,warmer,and favorable conditions that support a greater variety of species.
53
EasyMCQ
Given below are two statements.
Statement-$I$: Availability of intense sunlight,warmer temperature and higher annual rainfall in the tropics are responsible for species richness of fruit-yielding trees.
Statement-$II$: The variety of frugivorous organisms is more in the tropics as compared to the temperate regions.
In light of the above statements,choose the most appropriate answer from the options given below.
A
Both Statement-$I$ and Statement-$II$ are incorrect.
B
Statement-$I$ is correct and Statement-$II$ is incorrect.
C
Statement-$I$ is incorrect and Statement-$II$ is correct.
D
Both Statement-$I$ and Statement-$II$ are correct.

Solution

(D) Statement-$I$ is correct: Tropical regions receive more solar energy,which contributes to higher productivity. This favorable climate,characterized by intense sunlight,warmer temperatures,and higher annual rainfall,supports a greater diversity of plant species,including fruit-yielding trees.
Statement-$II$ is correct: Due to the high diversity of fruit-yielding trees in the tropics,there is a corresponding increase in the variety of frugivorous (fruit-eating) organisms that depend on these resources. This diversity is significantly higher in the tropics compared to temperate regions,which have less stable and less productive climates.
54
EasyMCQ
Species diversity is bountiful in the tropics near the equator because of the following factors $EXCEPT$ . . . . . .
A
higher annual rainfall.
B
warmer temperature
C
intense sunlight
D
drastic seasonal climatic changes.

Solution

(D) The tropics near the equator exhibit high species diversity due to several favorable environmental conditions. These include:
$1$. Higher annual rainfall,which supports diverse vegetation.
$2$. Warmer temperatures,which promote metabolic activity and growth.
$3$. Intense sunlight,which provides abundant energy for primary productivity.
Conversely,drastic seasonal climatic changes are characteristic of temperate regions,not the tropics. The tropics are relatively stable,which allows for niche specialization and higher biodiversity. Therefore,the factor that does $NOT$ contribute to high species diversity in the tropics is drastic seasonal climatic changes.
55
EasyMCQ
According to the hypothesis proposed by environmental biologists,a relatively constant environment in the tropics promotes:
A
Niche specialization and lesser species diversity
B
Niche specialization and greater species diversity
C
Niche diversity and lesser species specialization
D
Niche diversity and greater species specialization

Solution

(B) The correct answer is $B$.
Environmental biologists suggest that the relatively constant and stable climate in tropical regions allows for $Niche$ specialization.
Because the environment is stable and provides consistent favorable conditions along with abundant solar energy,it supports the evolution of a wider variety of species,leading to greater species diversity.
56
EasyMCQ
The given graph represents:
Question diagram
A
population growth
B
enzyme activity
C
species-area relationship
D
growth of organisms

Solution

(C) The given graph represents the species-area relationship.
Alexander von Humboldt observed that within a region,species richness increases with increasing explored area,but only up to a limit.
The relationship is described by the equation $S = CA^Z$,where:
$S$ = Species richness
$A$ = Area
$Z$ = Slope of the line (regression coefficient)
$C$ = $Y$-intercept
On a logarithmic scale,this relationship becomes a straight line described by the equation $\log S = \log C + Z \log A$.
57
EasyMCQ
The correct equation depicting the species-area relationship is:
A
logS = logC + ZlogA
B
logC = logS + ZlogA
C
logA = logC + ZlogA
D
logZ = logC + ZlogA

Solution

(A) The species-area relationship was proposed by Alexander von Humboldt.
The relationship is represented by the equation $S = CA^Z$.
Taking the logarithm on both sides,we get:
$\log S = \log(CA^Z)$
$\log S = \log C + \log(A^Z)$
$\log S = \log C + Z \log A$
Therefore,the correct equation is $\log S = \log C + Z \log A$.
58
EasyMCQ
Match $M$ and $N$ with the species-area relationship shown in the graphic representation below and choose the correct option.
Question diagram
A
$M \rightarrow S = CA^Z, N \rightarrow \log S = \log C + Z \log A$
B
$M \rightarrow S = CZ^A, N \rightarrow \log C = \log S + Z \log A$
C
$M \rightarrow S = CA^Z, N \rightarrow \log S = \log C + A \log Z$
D
$M \rightarrow S = AZ^C, N \rightarrow \log ZA = \log C + \log S$

Solution

(A) The correct option is $A$.
In the given graph,$M$ represents the species-area relationship on a normal scale,which is a rectangular hyperbola described by the equation $S = CA^Z$.
$N$ represents the same relationship on a logarithmic scale,which results in a straight line described by the equation $\log S = \log C + Z \log A$.
Here,$S$ represents species richness,$A$ represents area,$Z$ represents the slope of the line (regression coefficient),and $C$ represents the $Y$-intercept.

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