Write the unit of the rate constant for the following reactions:
$1.$ $5/2$ order
$2.$ $n$ order

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(N/A) The general formula for the unit of the rate constant $(k)$ for a reaction of order $n$ is given by:
$k = (\text{concentration})^{1-n} \times (\text{time})^{-1}$
Using molarity $(M = \text{mol L}^{-1})$ and time in seconds $(s)$:
$1.$ For $n = 5/2$:
Unit $= (\text{mol L}^{-1})^{1 - 5/2} \times s^{-1} = (\text{mol L}^{-1})^{-3/2} \times s^{-1} = \text{mol}^{-3/2} \text{L}^{3/2} \text{s}^{-1}$
$2.$ For $n$ order:
Unit $= (\text{mol L}^{-1})^{1-n} \text{s}^{-1}$

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The mechanism of the reaction,$2NO_{(g)} + 2H_{2(g)} \to N_{2(g)} + 2H_2O_{(g)}$ is:
Step $1$: $2NO_{(g)} + H_{2(g)} \xrightarrow{\text{slow}} N_2 + H_2O_2$
Step $2$: $H_2O_2 + H_2 \xrightarrow{\text{fast}} 2H_2O$
Then the correct statement is:

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For a reaction of order $n$,the unit of the rate constant is :

How can you determine the rate law of the following reaction?
$2 \, NO \, (g) + O_2 \, (g) \to 2 \, NO_2 \, (g)$

Identify the rate law expression for the reaction $2 NO_{(g)} + Cl_{2(g)} \rightarrow 2 NOCl_{(g)}$ if the reaction is second order in $NO$ and first order in $Cl_2$.

Which of the following statements is correct?

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