Write the following sets in roster form :
$D = \{ x:x$ is a prime number which is divisor of $60\} $
$D = \{ x:x$ is a prime number which is divisor of $60\} $
$2$ | $60$ |
$2$ | $30$ |
$3$ | $15$ |
$5$ |
$\therefore 60=2 \times 2 \times 3 \times 5$
The elements of this set are $2,3$ and $5$ only.
Therefore, this set can be written in roster form as $D=\{2,3,5\}$
Given the sets $A=\{1,3,5\}, B=\{2,4,6\}$ and $C=\{0,2,4,6,8\},$ which of the following may be considered as universal set $(s)$ for all the three sets $A$, $B$ and $C$
$\varnothing$
Consider the sets
$\phi, A=\{1,3\}, B=\{1,5,9\}, C=\{1,3,5,7,9\}$
Insert the symbol $\subset$ or $ \not\subset $ between each of the following pair of sets:
$B \ldots \cdot C$
The number of elements in the set $\{x \in R :(|x|-3)|x+4|=6\}$ is equal to
Let $A=\{1,2,3,4,5,6\} .$ Insert the appropriate symbol $\in$ or $\notin$ in the blank spaces:
$ 8\, .......\, A $
Write the following sets in roster form :
$\mathrm{F} =$ The set of all letters in the word $\mathrm{BETTER}$