(A) Given the $n^{th}$ term is $a_{n} = n(n+2)$.Substituting $n = 1, 2, 3, 4, 5$:For $n = 1: a_{1} = 1(1+2) = 3$For $n = 2: a_{2} = 2(2+2) = 8$For $n

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(A) Given the $n^{th}$ term is $a_{n} = n(n+2)$.Substituting $n = 1, 2, 3, 4, 5$:For $n = 1: a_{1} = 1(1+2) = 3$For $n = 2: a_{2} = 2(2+2) = 8$For $n = 3: a_{3} = 3(3+2) = 15$For $n = 4: a_{4} = 4(4+2) = 24$For $n = 5: a_{5} = 5(5+2) = 35$Thus,the first five terms are $3, 8, 15, 24, 35$.

Class 11 Mathematics Sequences and Series nth term of special series, Sum to n terms and Infinite number of terms

Easy

Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = n(n+2)$.

A
$3, 8, 15, 24, 35$
B
$3, 8, 15, 24, 36$
C
$2, 8, 15, 24, 35$
D
$3, 8, 16, 24, 35$

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nth term of special series, Sum to n terms and Infinite number of terms

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Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = n(n+2)$.

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