Write the differential rate expression for the following reactions and determine their order of reaction:
$1) \ 2 N_2O_5(g) \rightarrow 4 NO_2(g) + O_2(g)$
$2) \ C_4H_9Cl(aq) + OH^-(aq) \rightarrow C_4H_9OH(aq) + Cl^-(aq)$

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For reaction $1$: $2 N_2O_5 \rightarrow 4 NO_2 + O_2$
The differential rate expression is: $Rate = -\frac{1}{2} \frac{d[N_2O_5]}{dt} = \frac{1}{4} \frac{d[NO_2]}{dt} = \frac{d[O_2]}{dt}$.
This is a first-order reaction with respect to $N_2O_5$,so the overall order of reaction is $1$.
For reaction $2$: $C_4H_9Cl + OH^- \rightarrow C_4H_9OH + Cl^-$
The differential rate expression is: $Rate = -\frac{d[C_4H_9Cl]}{dt} = -\frac{d[OH^-]}{dt} = \frac{d[C_4H_9OH]}{dt} = \frac{d[Cl^-]}{dt}$.
This is a nucleophilic substitution reaction (specifically $S_N2$ mechanism),which is a second-order reaction (first order with respect to both $C_4H_9Cl$ and $OH^-$),so the overall order of reaction is $2$.

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For a hypothetical reaction,$A \rightarrow C$. The mechanism is: $A \underset{k_2}{\stackrel{k_1}{\rightleftharpoons}} B$ (Fast),$A + B \xrightarrow{k_3} C$ (Slow). The rate law for this reaction is:

For the reaction $A_2 + B_2 \to 2AB$,the experimental data is given below. Determine the order of the reaction.
Experiment No. $[A_2] \text{ (M)}$ $[B_2] \text{ (M)}$ Rate $(M \cdot s^{-1})$
$1$ $0.1$ $0.1$ $1.6 \times 10^{-4}$
$2$ $0.1$ $0.2$ $3.2 \times 10^{-4}$
$3$ $0.2$ $0.1$ $3.2 \times 10^{-4}$

The unit of rate constant $K$ for a third-order reaction is . . . . . . .

Considering the reaction $aG + bH \rightarrow \text{Products}$,when the concentrations of both reactants $G$ and $H$ are doubled,the rate increases by $8$ times. However,when the concentration of $G$ is doubled while the concentration of $H$ remains constant,the rate doubles. What is the overall order of the reaction?

In a reaction between $A$ and $B$,the initial rate of reaction $(r_0)$ was measured for different initial concentrations of $A$ and $B$ as given below:
$A / mol \ L^{-1}$ $0.20$ $0.20$ $0.40$
$B / mol \ L^{-1}$ $0.30$ $0.10$ $0.05$
$r_0 / mol \ L^{-1} \ s^{-1}$ $5.07 \times 10^{-5}$ $5.07 \times 10^{-5}$ $1.43 \times 10^{-4}$

What is the order of the reaction with respect to $A$ and $B$?

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