Write a note about the energy of orbitals in hydrogen.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) The energy of an electron in a hydrogen atom is determined solely by the principal quantum number $(n)$. Thus,the energy of the orbitals increases as follows:
$1s < 2s = 2p < 3s = 3p = 3d < 4s = 4p = 4d = 4f < 5s = 5p = \dots$
Ground state of $H$: The $1s$ orbital in a hydrogen atom corresponds to the most stable condition and is called the ground state,and an electron residing in this orbital is most strongly held by the nucleus.
Excited state: An electron in the $2s, 2p$ or higher orbitals in a hydrogen atom is in an excited state.
An electron in an excited state is weakly attracted towards the nucleus. Ground state energy < Excited state energy.
The only electrical interaction present in the hydrogen atom is the attraction between the negatively charged electron and the positively charged nucleus; therefore,the subshell $(l)$ does not affect the orbital energy state.

Explore More

Similar Questions

The total number of magnetic quantum numbers for a $d$-orbital is given by

The electronic configuration $1s^{2}\, 2s^{2}\, 2p^{5}\, 3s^{1}$ represents:

After filling the $4d$ orbitals,an electron will enter in:

Which of the following sequences is correct according to the Aufbau principle?

Which one of the following sets of quantum numbers represents an impossible arrangement?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo