Words with or without meaning are to be forme | vedclass

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Question

$AAEIIMNNOTX$

Total words $=\frac{11:}{2: 2: 21}=\mathrm{n}(\mathrm{s})$

$\quad\quad M$

$\underline{}$$\,\underline{}$$\,\underline{}$$\,\und

Vedclass · Accepted Answer

$\frac{1}{11}$

Vedclass · Answer

$AAEIIMNNOTX$

Total words $=\frac{11:}{2: 2: 21}=\mathrm{n}(\mathrm{s})$

$\quad\quad M$

$\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$$\,\underline{}$

Total words with $\mathrm{M}$ at fourth place $=\frac{10 !}{2 ! 2 ! 2 !}=n(\mathrm{~A})$

$	ext { Probability }=\frac{10 !}{11 !}=\frac{1}{11}$

Words with or without meaning are to be formed using all the letters of the word $EXAMINATION.$ The probability that the letter $\mathrm{M}$ appears at the fourth position in any such word is:

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