Which one of the following does not have $sp^2$ hybridised carbon?

Determine the hybridization of the carbon atoms in the following compounds:
$(a)$ $N \equiv C-CH=CH_2$
$(b)$ $HC \equiv C-CH=CH_2$ (Identify the carbon atoms of the single bond $C-C$)
$(c)$ $HC \equiv C-C \equiv CH$
$(d)$ $H_2C=C=C=CH_2$
$(e)$ Buta$-1,3-$diene (as shown in the figure)

Hybridization of $1$ and $2$ carbon atoms in $\mathop {CH_2}\limits^1 = \mathop C\limits^2 = CH_2$

Match the following lists:

List-$I$	List-$II$
$A$. Ethane	$1$. $2 \ sp$ carbons
$B$. Ethylene	$2$. $6 \ sp^2$ carbons
$C$. Acetylene	$3$. $2 \ sp^3$ carbons
$D$. Benzene	$4$. $2 \ sp^2$ carbons
	$5$. $1 \ sp$ and $1 \ sp^2$ carbons

In the given molecule $(NC)_3 CCCCHCHBr$,the number of $\sigma$ and $\pi$ bonds respectively are:

In the given structure,the number of $sp$ and $sp^{2}$ hybridized carbon atoms present respectively are: