Hybridization of 1 and 2 carbon atoms in math | vedclass

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(C) In the molecule $\mathop {CH_2}\limits^1 = \mathop C\limits^2 = CH_2$,the carbon atom at position $1$ is bonded to two hydrogen atoms and one carb

Vedclass · Accepted Answer

$sp^2, sp$

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(C) In the molecule $\mathop {CH_2}\limits^1 = \mathop C\limits^2 = CH_2$,the carbon atom at position $1$ is bonded to two hydrogen atoms and one carbon atom via a double bond. It has $3$ sigma bonds and $0$ lone pairs,resulting in $sp^2$ hybridization.The carbon atom at position $2$ is bonded to two carbon atoms via two double bonds. It has $2$ sigma bonds and $0$ lone pairs,resulting in $sp$ hybridization.Therefore,the hybridization of carbon $1$ is $sp^2$ and carbon $2$ is $sp$.

Hybridization of $1$ and $2$ carbon atoms in $\mathop {CH_2}\limits^1 = \mathop C\limits^2 = CH_2$

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