In the given structure,the number of sp and s | vedclass

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(A) To determine the hybridization of carbon atoms,we count the number of sigma bonds and lone pairs (if any) attached to each carbon atom.$1$. $sp$ h

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$4$ and $5$

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(A) To determine the hybridization of carbon atoms,we count the number of sigma bonds and lone pairs (if any) attached to each carbon atom.$1$. $sp$ hybridized carbon: Carbon atom involved in two sigma bonds and two pi bonds (e.g.,triple bond or two double bonds).$2$. $sp^{2}$ hybridized carbon: Carbon atom involved in three sigma bonds and one pi bond (e.g.,double bond).In the given structure:- The carbon atoms in the triple bond (alkyne) and the nitrile group $(-C \equiv N)$ are $sp$ hybridized. There are $4$ such carbon atoms.- The carbon atoms in the double bonds (alkene) and the carbonyl group $(C=O)$ are $sp^{2}$ hybridized. There are $5$ such carbon atoms.Therefore,the number of $sp$ and $sp^{2}$ hybridized carbon atoms are $4$ and $5$ respectively.

In the given structure,the number of $sp$ and $sp^{2}$ hybridized carbon atoms present respectively are:

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