Which one of the following does not correctly | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For $Ti, V, Cr, Mn$,the number of oxidation states are $3, 4, 5, 6$ respectively. Thus,$Ti < V < Cr < Mn$ is correct.For magnetic moment $(\mu) =

Vedclass · Accepted Answer

$Ti < V < Cr < Mn$; increasing melting points

Vedclass · Answer

(C) For $Ti, V, Cr, Mn$,the number of oxidation states are $3, 4, 5, 6$ respectively. Thus,$Ti For magnetic moment $(\mu) = \sqrt{n(n+2)} \ B.M$:$Ti^{3+} (3d^1): n=1, \mu = \sqrt{3} \ B.M$$V^{3+} (3d^2): n=2, \mu = \sqrt{8} \ B.M$$Cr^{3+} (3d^3): n=3, \mu = \sqrt{15} \ B.M$$Mn^{3+} (3d^4): n=4, \mu = \sqrt{24} \ B.M$Thus,$Ti^{3+} The actual order of melting points is $Mn The $2^{nd}$ ionization enthalpy order is $Ti < V < Mn < Cr$,which is correct.

List-$I$ (Transition metal,$M$)	List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$)
$A$. $Ni$	$I$. $-1.18$
$B$. $Mn$	$II$. $-0.91$
$C$. $Fe$	$III$. $-0.25$
$D$. $Cr$	$IV$. $-0.44$

Which one of the following does not correctly represent the correct order of the property indicated against it?

Similar Questions

In the following pairs,the one in which both transition metal ions are colourless is

Of the following outer electronic configurations of atoms,the highest oxidation state is achieved by which one of them?

Why is the first ionisation enthalpy of $Cr$ lower than that of $Zn$?

The most stable oxidation state of $Mn$ is

Match the following:

List-$I$ (Transition metal,$M$) List-$II$ ($E_{M^{2+}/ M}^{\ominus}$ in $V$)

$A$. $Ni$ $I$. $-1.18$

$B$. $Mn$ $II$. $-0.91$

$C$. $Fe$ $III$. $-0.25$

$D$. $Cr$ $IV$. $-0.44$

The correct answer is

Vedclass Test Series

Exam Paper Generator

Online Exam Module