The correct order of decreasing third ionisation enthalpy of $Ti, \,V,\, Cr,\, Mn$ is
The correct order of decreasing third ionisation enthalpy of $Ti, \,V,\, Cr,\, Mn$ is
- A
$Mn > Cr > V > Ti$
- B
$Ti > V > Cr > Mn$
- C
$Cr > Mn > V > Ti$
- D
$V > Mn > Cr > Ti$
Similar Questions
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The correct order of decreasing third ionisation enthalpy of $Ti,\, V,\, Cr,\, Mn$ is
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Technetium, the element below manganese in the Periodic Table, would be expected to have high values for its
$(I)$ melting point $(II)$ boiling point $(III)$ density
Technetium, the element below manganese in the Periodic Table, would be expected to have high values for its
$(I)$ melting point $(II)$ boiling point $(III)$ density
Which of the following statements are correct?
$(A)$ The electronic configuration of $Cr$ is $[ Ar ] 3 d ^{5}$ $4 s^{1}$.
$(B)$ The magnetic quantum number may have a negative value.
$(C)$ In the ground state of an atom, the orbitals are filled in order of their increasing energies.
$(D)$ The total number of nodes are given by $n-2$.
Choose the most appropriate answer from the options given below ....
Which of the following statements are correct?
$(A)$ The electronic configuration of $Cr$ is $[ Ar ] 3 d ^{5}$ $4 s^{1}$.
$(B)$ The magnetic quantum number may have a negative value.
$(C)$ In the ground state of an atom, the orbitals are filled in order of their increasing energies.
$(D)$ The total number of nodes are given by $n-2$.
Choose the most appropriate answer from the options given below ....
- [JEE MAIN 2022]