Chloro compound of Vanadium has only spin mag | vedclass

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Question

$\mu  = \sqrt {n(n + 2)} $

$1.73 = \sqrt {n(n + 2)} $

On calculating the value of $n$ we find $n=1$

No. of unpaired electrons $= 1$

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Vedclass · Accepted Answer

$VCl_4$

Vedclass · Answer

$\mu  = \sqrt {n(n + 2)} $

$1.73 = \sqrt {n(n + 2)} $

On calculating the value of $n$ we find $n=1$

No. of unpaired electrons $= 1$

hence its consfiguration will be 

$V(23) = [Ar] 3d^3\,4s^2$

$V^{4+} = [Ar]3d^1$

Its chloride has the formula $VCl_4$

Chloro compound of Vanadium has only spin magnetic moment of $1.73\, BM$. This Vanadium chloride has the formula

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