Which one has the maximum oxidation number of | vedclass

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(C) To find the oxidation number of phosphorus $(P)$ in each compound,we use the rule that the sum of oxidation states in a neutral molecule is $0$. L

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$H_3PO_4$

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(C) To find the oxidation number of phosphorus $(P)$ in each compound,we use the rule that the sum of oxidation states in a neutral molecule is $0$. Let the oxidation state of $P$ be $x$.$1$. In $PH_3$: $x + 3(+1) = 0 \implies x = -3$.$2$. In $H_4P_2O_6$: $4(+1) + 2x + 6(-2) = 0 \implies 4 + 2x - 12 = 0 \implies 2x = 8 \implies x = +4$.$3$. In $H_3PO_4$: $3(+1) + x + 4(-2) = 0 \implies 3 + x - 8 = 0 \implies x = +5$.$4$. In $H_3PO_3$: $3(+1) + x + 3(-2) = 0 \implies 3 + x - 6 = 0 \implies x = +3$.Comparing the values $(-3, +4, +5, +3)$,the maximum oxidation number is $+5$,which corresponds to $H_3PO_4$.

Which one has the maximum oxidation number of phosphorus?

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