Two unit negative charges are placed on a str | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let the two unit negative charges be $q_1 = -1 \ C$ and $q_2 = -1 \ C$,separated by a distance $d$.For the system to be in equilibrium,the net for

Vedclass · Accepted Answer

$0.25$

Vedclass · Answer

(A) Let the two unit negative charges be $q_1 = -1 \ C$ and $q_2 = -1 \ C$,separated by a distance $d$.For the system to be in equilibrium,the net force on each charge must be zero.Consider the equilibrium of charge $q_1$ at point $A$. The force exerted by $q$ at $B$ and $q_2$ at $C$ on $q_1$ must sum to zero:$F_{AB} + F_{AC} = 0$$\frac{1}{4 \pi \varepsilon_0} \frac{q_1 q}{(d/2)^2} + \frac{1}{4 \pi \varepsilon_0} \frac{q_1 q_2}{d^2} = 0$Dividing by $\frac{q_1}{4 \pi \varepsilon_0}$,we get:$\frac{q}{(d/2)^2} + \frac{q_2}{d^2} = 0$$\frac{q}{d^2/4} + \frac{-1}{d^2} = 0$$\frac{4q}{d^2} = \frac{1}{d^2}$$4q = 1$$q = 0.25 \ C$

Two unit negative charges are placed on a straight line. $A$ positive charge $q$ is placed exactly at the midpoint between these unit charges. If the system of these three charges is in equilibrium,the value of $q$ (in $C$) is

Similar Questions

The radius of the circle $r = \sqrt{3} \sin \theta + \cos \theta$ is

The electronic configuration of a metal $M$ is $1s^2 \, 2s^2 \, 2p^6 \, 3s^1$. What will be the formula of its oxide?

If the series limit of the Lyman series for a Hydrogen atom is equal to the series limit of the Balmer series for a hydrogen-like atom,then the atomic number of this hydrogen-like atom will be:

Which of the following is not a unit of time?

Vedclass Test Series

Exam Paper Generator

Online Exam Module