In a potentiometer experiment,the balancing l | vedclass

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(D) The balancing length for the cell is $\ell_0 = 240 \ cm$.When a resistance $R = 2 \ \Omega$ is connected in parallel,the balancing length is $\ell

Vedclass · Accepted Answer

$2$

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(D) The balancing length for the cell is $\ell_0 = 240 \ cm$.When a resistance $R = 2 \ \Omega$ is connected in parallel,the balancing length is $\ell_C = 120 \ cm$.The formula for the internal resistance $r$ of a cell using a potentiometer is given by $r = R \left( \frac{\ell_0 - \ell_C}{\ell_C} ight)$.Substituting the given values:$r = 2 \left( \frac{240 - 120}{120} ight) \ \Omega$.$r = 2 \left( \frac{120}{120} ight) \ \Omega$.$r = 2 	imes 1 \ \Omega = 2 \ \Omega$.Therefore,the internal resistance of the cell is $2 \ \Omega$.

In a potentiometer experiment,the balancing length for a cell is $240 \ cm$. When a resistance of $2 \ \Omega$ is connected in parallel with the cell,the balancing length becomes $120 \ cm$. The internal resistance of the cell is ................. $\Omega$.

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