(C) In $[Co(CN)_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^6$. Since $CN^-$ is a strong field liga

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$[Co(CN)_6]^{3-}$ has no unpaired electrons and will be in a low-spin configuration.

(C) In $[Co(CN)_6]^{3-}$,the oxidation state of $Co$ is $+3$. The electronic configuration of $Co^{3+}$ is $3d^6$. Since $CN^-$ is a strong field ligand,it causes pairing of electrons in the $3d$ orbitals. This results in all $6$ electrons being paired in the $t_{2g}$ orbitals. Therefore,the complex has no unpaired electrons and is a low-spin complex.

Class 12 Chemistry Coordination Compounds Hybridisation and Geometry

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Which of these statements about $[Co(CN)_6]^{3-}$ is true?

NEET 2015 All NEET

A
$[Co(CN)_6]^{3-}$ has four unpaired electrons and will be in a high-spin configuration.
B
$[Co(CN)_6]^{3-}$ has no unpaired electrons and will be in a high-spin configuration.
C
$[Co(CN)_6]^{3-}$ has no unpaired electrons and will be in a low-spin configuration.
D
$[Co(CN)_6]^{3-}$ has four unpaired electrons and will be in a low-spin configuration.

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The incorrect statement about $Ni(CO)_4$ is

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Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?

DifficultAIPMT 2012

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The geometries of $Ni(CO)_4$ and $Ni(PPh_3)_2Cl_2$ are:

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Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

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Consider the transition metal ions $Mn^{3+}$,$Cr^{3+}$,$Fe^{3+}$,and $Co^{3+}$. All form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$-orbitals of the complexes is:

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Which of these statements about $[Co(CN)_6]^{3-}$ is true?

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The incorrect statement about $Ni(CO)_4$ is

Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?

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Which of the following complexes does not match with the hybridization state of its metal ion?$(i) [Ni(CO)_4], sp^3$$(ii) [Ni(CN)_4]^{2-}, sp^3$$(iii) [CoF_6]^{3-}, d^2sp^3$$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

Consider the transition metal ions $Mn^{3+}$,$Cr^{3+}$,$Fe^{3+}$,and $Co^{3+}$. All form low spin octahedral complexes. The correct decreasing order of unpaired electrons in their respective $d$-orbitals of the complexes is:

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Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$