Which one of the following is an outer orbita | vedclass

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(A) For $[Ni(NH_3)_6]^{2+}$,the oxidation state of $Ni$ is $+2$ ($3d^8$ configuration). It uses $4s, 4p,$ and $4d$ orbitals to form $sp^3d^2$ hybrid o

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$[Ni(NH_3)_6]^{2+}$

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(A) For $[Ni(NH_3)_6]^{2+}$,the oxidation state of $Ni$ is $+2$ ($3d^8$ configuration). It uses $4s, 4p,$ and $4d$ orbitals to form $sp^3d^2$ hybrid orbitals,making it an outer orbital complex. It has two unpaired electrons in the $3d$ orbitals,so it is paramagnetic.For $[Zn(NH_3)_6]^{2+}$,the oxidation state of $Zn$ is $+2$ ($3d^{10}$ configuration). It is an outer orbital complex $(sp^3d^2)$,but it is diamagnetic due to no unpaired electrons.For $[Cr(NH_3)_6]^{3+}$,the oxidation state of $Cr$ is $+3$ ($3d^3$ configuration). It uses $3d, 4s,$ and $4p$ orbitals to form $d^2sp^3$ hybrid orbitals,making it an inner orbital complex. It is paramagnetic.For $[Co(NH_3)_6]^{3+}$,the oxidation state of $Co$ is $+3$ ($3d^6$ configuration). It forms $d^2sp^3$ hybrid orbitals,making it an inner orbital complex. It is diamagnetic.

List-$I$ (Complex/ion)	List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$	$I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$	$II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$	$III$. Square planar
$D$. $[Fe(CO)_5]$	$IV$. Tetrahedral

Which one of the following is an outer orbital complex and exhibits paramagnetic behaviour?

Similar Questions

Match List-$I$ with List-$II$:
List-$I$ (Complex/ion) List-$II$ (Shape/geometry)
$A$. $[Pt(Cl)_2(NH_3)_2]$ $I$. Octahedral
$B$. $[Co(NH_3)_6]Cl_3$ $II$. Trigonal bipyramidal
$C$. $[NiCl_4]^{2-}$ $III$. Square planar
$D$. $[Fe(CO)_5]$ $IV$. Tetrahedral

Which of the following statements is incorrect regarding $[Ni(dmg)_2]$?

Which of the following is not a square planar complex?

An octahedral complex of $Ni(II)$ must be:

The $Cl-Co-Cl$ bond angle values in a $fac-[Co(NH_3)_3Cl_3]$ complex is/are:

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