Which of the following complexes does not mat | vedclass

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(D) $1$. For $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing. Hybridization is $sp^3$. (Corr

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$(ii), (iii)$ and $(iv)$

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(D) $1$. For $[Ni(CO)_4]$: $Ni$ is in $0$ oxidation state $(3d^8 4s^2)$. $CO$ is a strong field ligand,causing pairing. Hybridization is $sp^3$. (Correct)$2$. For $[Ni(CN)_4]^{2-}$: $Ni$ is in $+2$ oxidation state $(3d^8)$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $dsp^2$. (Incorrect,given as $sp^3$)$3$. For $[CoF_6]^{3-}$: $Co$ is in $+3$ oxidation state $(3d^6)$. $F^-$ is a weak field ligand,no pairing. Hybridization is $sp^3d^2$. (Incorrect,given as $d^2sp^3$)$4$. For $[Fe(CN)_6]^{3-}$: $Fe$ is in $+3$ oxidation state $(3d^5)$. $CN^-$ is a strong field ligand,causing pairing. Hybridization is $d^2sp^3$. (Incorrect,given as $sp^3d^2$)Thus,$(ii), (iii),$ and $(iv)$ do not match.

Hybridisation	Geometry	Complex structure
$(A) \ sp^3$	$(i) \ \text{Square planar}$	$(p) \ [Fe(CN)_6]^{3-}$
$(B) \ d^2sp^3$	$(ii) \ \text{Tetrahedral}$	$(q) \ [ZnCl_4]^{2-}$
$(C) \ dsp^2$	$(iii) \ \text{Octahedral}$	$(r) \ [Ni(NH_3)_4]^{2+}$
-	$(iv) \ \text{Linear}$	$(s) \ [Ag(CN)_2]^-$

Which of the following complexes does not match with the hybridization state of its metal ion?
$(i) [Ni(CO)_4], sp^3$
$(ii) [Ni(CN)_4]^{2-}, sp^3$
$(iii) [CoF_6]^{3-}, d^2sp^3$
$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$

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Which of the following complexes does not match with the hybridization state of its metal ion?$(i) [Ni(CO)_4], sp^3$$(ii) [Ni(CN)_4]^{2-}, sp^3$$(iii) [CoF_6]^{3-}, d^2sp^3$$(iv) [Fe(CN)_6]^{3-}, sp^3d^2$