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(A) Two solutions are isotonic if their osmotic pressures are equal.Osmotic pressure $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is molarity,$

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$0.01 \ M \ BaCl_2$ and $0.015 \ M \ NaCl$

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(A) Two solutions are isotonic if their osmotic pressures are equal.Osmotic pressure $\pi = iCRT$,where $i$ is the van't Hoff factor,$C$ is molarity,$R$ is the gas constant,and $T$ is temperature.For isotonic solutions at the same temperature,the effective concentration $(i 	imes C)$ must be equal.$(A)$ For $0.01 \ M \ BaCl_2$: $i = 3$,$C = 0.01$,$i 	imes C = 0.03$. For $0.015 \ M \ NaCl$: $i = 2$,$C = 0.015$,$i 	imes C = 0.03$. Since $0.03 = 0.03$,this pair is isotonic.$(B)$ For $0.001 \ M \ Al_2(SO_4)_3$: $i = 5$,$C = 0.001$,$i 	imes C = 0.005$. For $0.001 \ M \ BaCl_2$: $i = 3$,$C = 0.001$,$i 	imes C = 0.003$. Not isotonic.$(C)$ For $0.001 \ M \ CaCl_2$: $i = 3$,$C = 0.001$,$i 	imes C = 0.003$. For $0.001 \ M \ Al_2(SO_4)_3$: $i = 5$,$C = 0.001$,$i 	imes C = 0.005$. Not isotonic.$(D)$ For $0.01 \ M \ BaCl_2$: $i 	imes C = 0.03$. For $0.001 \ M \ CaCl_2$: $i 	imes C = 0.003$. Not isotonic.Thus,the correct option is $(A)$.

Which of the following pairs of solutions is isotonic?

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