Calculate the osmotic pressure of 0.03 mol o | vedclass

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(A) The formula for osmotic pressure $(\pi)$ is given by $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant,and $T$ is the tempe

Vedclass · Accepted Answer

$7.4$

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(A) The formula for osmotic pressure $(\pi)$ is given by $\pi = CRT$,where $C$ is the molar concentration,$R$ is the gas constant,and $T$ is the temperature in Kelvin.First,calculate the molar concentration $(C)$:$C = \frac{n}{V} = \frac{0.03 \ mol}{0.1 \ dm^3} = 0.3 \ mol \ dm^{-3}$.Now,substitute the values into the formula:$\pi = 0.3 \ mol \ dm^{-3} 	imes 0.0821 \ dm^3 \ atm \ mol^{-1} \ K^{-1} 	imes 300 \ K$.$\pi = 0.3 	imes 0.0821 	imes 300 \ atm$.$\pi = 7.389 \ atm \approx 7.4 \ atm$.

Calculate the osmotic pressure of $0.03 \ mol$ of non-electrolyte solute dissolved in $0.1 \ dm^3$ of water at $300 \ K \ [R=0.0821 \ dm^3 \ atm \ mol^{-1} \ K^{-1}]$ (in $atm$)

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