Which of the following molecules/ions does no | vedclass

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(C) According to Molecular Orbital Theory $(MOT)$,we determine the presence of unpaired electrons by filling the molecular orbitals:$1$. For $N_2^+$ (

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$O_2^{2-}$

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(C) According to Molecular Orbital Theory $(MOT)$,we determine the presence of unpaired electrons by filling the molecular orbitals:$1$. For $N_2^+$ ($13$ electrons): $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p_x}^2 \pi_{2p_y}^2 \sigma_{2p_z}^1$. It has $1$ unpaired electron.$2$. For $O_2$ ($16$ electrons): $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^{*1} \pi_{2p_y}^{*1}$. It has $2$ unpaired electrons.$3$. For $O_2^{2-}$ ($18$ electrons): $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \sigma_{2p_z}^2 \pi_{2p_x}^2 \pi_{2p_y}^2 \pi_{2p_x}^{*2} \pi_{2p_y}^{*2}$. All electrons are paired.$4$. For $B_2$ ($10$ electrons): $\sigma_{1s}^2 \sigma_{1s}^{*2} \sigma_{2s}^2 \sigma_{2s}^{*2} \pi_{2p_x}^1 \pi_{2p_y}^1$. It has $2$ unpaired electrons.Therefore,$O_2^{2-}$ is the only species without unpaired electrons.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

Which of the following molecules/ions does not contain unpaired electrons?

Similar Questions

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

Which one of the following pairs of species have the same bond order?

The number of anti-bonding electrons present in $O_{2}^{-}$ molecular ion is

The oxygen molecule $(O_2)$ exhibits which of the following magnetic properties?

Which of the following species contains only $\pi$-bonds but exhibits paramagnetic nature?

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