Assertion :Fluorine molecule has bond order o | vedclass

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Question

$MO$ electronic configuration of $F_2$ molecule. $\sigma 1{s^2},\,{\sigma ^*}1{s^2},\,\sigma 2{s^2},\,{\sigma ^*}2{s^2},\,\sigma 2p_x^2,\,\pi 2p_y^2 \

Vedclass · Accepted Answer

If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.

Vedclass · Answer

$MO$ electronic configuration of $F_2$ molecule. $\sigma 1{s^2},\,{\sigma ^*}1{s^2},\,\sigma 2{s^2},\,{\sigma ^*}2{s^2},\,\sigma 2p_x^2,\,\pi 2p_y^2 \approx \,\pi 2p_z^2,\,{\pi ^*}2p_y^2 \approx {\pi ^*}2p_z^2$ Thus there are $10$ electrons in bonding orbitals and $8$ electrons in antibonding orbitals. Thus, reason is true and it is also the correct explanation of assertion because Bond order $=$ $\frac{{{N_b} - {N_a}}}{2} = \frac{{10 - 8}}{2} = 1$

Assertion :Fluorine molecule has bond order one.
Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.

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Assertion :Fluorine molecule has bond order one. Reason : The number of electrons in the antibonding molecular orbitals is two less than that in bonding molecular orbitals.