In which of the following processes does the | vedclass

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(B) To determine the change in bond order and magnetic nature,we analyze the molecular orbital configurations:$1$. For $O_2 (16e^-)$: Bond order = $2.

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$N_2^+ 	o N_2^-$

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(B) To determine the change in bond order and magnetic nature,we analyze the molecular orbital configurations:$1$. For $O_2 (16e^-)$: Bond order = $2.0$,Paramagnetic. For $O_2^+ (15e^-)$: Bond order = $2.5$,Paramagnetic. (Both change).$2$. For $N_2^+ (13e^-)$: Bond order = $2.5$,Paramagnetic. For $N_2^- (15e^-)$: Bond order = $2.5$,Paramagnetic. (Bond order and magnetic nature remain unchanged).$3$. For $NO (15e^-)$: Bond order = $2.5$,Paramagnetic. For $NO^+ (14e^-)$: Bond order = $3.0$,Diamagnetic. (Both change).$4$. For $CO (14e^-)$: Bond order = $3.0$,Diamagnetic. For $CO^+ (13e^-)$: Bond order = $2.5$,Paramagnetic. (Both change).Thus,the process $N_2^+ 	o N_2^-$ maintains both properties.

List-$I$ (Molecule)	List-$II$ (Number and types of bond/s between two carbon atoms)
$A.$ Ethane	$I.$ One $\sigma$-bond and two $\pi$-bonds
$B.$ Ethene	$II.$ Two $\pi$-bonds
$C.$ Carbon molecule,$C_2$	$III.$ One $\sigma$-bond
$D.$ Ethyne	$IV.$ One $\sigma$-bond and one $\pi$-bond

In which of the following processes does the value of bond order and magnetic nature not change?

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