Which of the following is incorrectly matched | vedclass

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(C) Let us analyze each complex:$A$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $3d^5$. $F^-$ is a weak field ligand,so no pairing occurs. Unpaired electrons $(n)$

Vedclass · Accepted Answer

Complex $[Co(NH_3)_6]^{3+}$,Number of unpaired electrons $\rightarrow 4$

Vedclass · Answer

(C) Let us analyze each complex:$A$. $[FeF_6]^{3-}$: $Fe^{3+}$ is $3d^5$. $F^-$ is a weak field ligand,so no pairing occurs. Unpaired electrons $(n)$ = $5$. (Correctly matched)$B$. $[Cr(en)_3]^{2+}$: $Cr^{2+}$ is $3d^4$. $en$ is a strong field ligand,causing pairing. The $3d^4$ configuration becomes $t_{2g}^4 e_g^0$,resulting in $n = 2$. (Correctly matched)$C$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing all electrons to pair up in the $t_{2g}$ orbitals. Thus,$n = 0$. The given value $4$ is incorrect. (Incorrectly matched)$D$. $[Mn(H_2O)_6]^{2+}$: $Mn^{2+}$ is $3d^5$. $H_2O$ is a weak field ligand,so no pairing occurs. $n = 5$. (Correctly matched)Therefore,the incorrectly matched option is $C$.

List-$I$ (Complex ion)	List-$II$ (Calculated spin only magnetic moment $(BM)$)
$A$. $[Cr(H_2O)_6]^{2+}$	$I$. $3.87$
$B$. $[Co(H_2O)_6]^{2+}$	$II$. $5.92$
$C$. $[Cu(H_2O)_6]^{2+}$	$III$. $4.90$
$D$. $[Mn(H_2O)_6]^{2+}$	$IV$. $1.73$

Which of the following is incorrectly matched?

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