On treatment of [Ni(NH_3)_4]^{2+} with concen | vedclass

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(B) The complex $[Ni(NH_3)_4]^{2+}$ has a square planar geometry. When treated with $HCl,$ it forms two isomers of $[Ni(NH_3)_2Cl_2].$ $I$ is the $cis

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$I$ cis,$II$ trans; both square planar

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(B) The complex $[Ni(NH_3)_4]^{2+}$ has a square planar geometry. When treated with $HCl,$ it forms two isomers of $[Ni(NH_3)_2Cl_2].$ $I$ is the $cis$-isomer and $II$ is the $trans$-isomer. Both isomers possess a square planar geometry because $Ni^{2+}$ in this coordination environment typically undergoes $dsp^2$ hybridization. Oxalic acid is a bidentate ligand that can form a chelate ring by replacing two $cis$ ligands. Since $I$ reacts with oxalic acid,it must be the $cis$-isomer,while $II$ is the $trans$-isomer which does not react because the $Cl$ atoms are not adjacent.

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