(A) $Cu^{+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). $Zn^{2+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). Therefo

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Aqueous solutions of $Cu^{+}$ and $Zn^{2+}$ are colourless

(A) $Cu^{+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). $Zn^{2+} = [Ar] 3d^{10}$ (No unpaired electrons,so it is colourless). Therefore,aqueous solutions of $Cu^{+}$ and $Zn^{2+}$ are colourless. $Cu^{2+} = [Ar] 3d^9$ (One unpaired electron is present,so it is coloured). $Fe^{3+}$ is yellow/brown in aqueous solution. $MnO_4^{-}$ is purple due to charge transfer,despite having no unpaired electrons. Thus,the statement in option $(A)$ is correct.

Class 12 Chemistry d-and f-Block Elements General Characteristics

Medium

Which of the following is a correct statement?

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A
Aqueous solutions of $Cu^{+}$ and $Zn^{2+}$ are colourless
B
Aqueous solutions of $Cu^{2+}$ and $Zn^{2+}$ are colourless
C
Aqueous solution of $Fe^{3+}$ is green in colour
D
Aqueous solution of $MnO_4^{-}$ is colourless

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Which of the following is a correct statement?

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Although Zirconium $(Zr)$ belongs to the $4d$-transition series and Hafnium $(Hf)$ belongs to the $5d$-transition series, they show similar physical and chemical properties because . . . . . . .

Which of the following sets correctly represents the increase in the paramagnetic property of the ions?

The $3d$ elements show variable oxidation states because the energies of the following sets of orbitals are almost similar:

Assertion $(A)$: While going from left to right in the periodic table,the atomic size decreases more rapidly for the $3d$-series compared to the $4f$-series of elements.Reason $(R)$: $3d$-electrons experience lesser shielding than $4f$-electrons.

Which one of the following does not correctly represent the correct order of the property indicated against it?

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Assertion $(A)$: While going from left to right in the periodic table,the atomic size decreases more rapidly for the $3d$-series compared to the $4f$-series of elements.
Reason $(R)$: $3d$-electrons experience lesser shielding than $4f$-electrons.