Although Zirconium (Zr) belongs to the 4d-tra | vedclass

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(A) The similarity in the properties of $Zr$ and $Hf$ is primarily due to the lanthanoid contraction. Due to the filling of $4f$ orbitals in the eleme

Vedclass · Accepted Answer

Both have similar atomic radii due to lanthanoid contraction.

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(A) The similarity in the properties of $Zr$ and $Hf$ is primarily due to the lanthanoid contraction. Due to the filling of $4f$ orbitals in the elements between $La$ and $Hf$, the atomic radius of $Hf$ $(159 	ext{ pm})$ is almost identical to that of $Zr$ $(160 	ext{ pm})$. This phenomenon is known as the lanthanoid contraction, which results in similar atomic and ionic radii for elements of the same group in the $4d$ and $5d$ series. Therefore, the correct answer is $A$.

Although Zirconium $(Zr)$ belongs to the $4d$-transition series and Hafnium $(Hf)$ belongs to the $5d$-transition series, they show similar physical and chemical properties because . . . . . . .

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