Which of the following electronic configurati | vedclass

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(D) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.   $3d$ confi

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$[Ar] 3d^6$

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(D) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.   $3d$ configuration Unpaired electrons $(n)$   $3d^7$ $3$   $3d^8$ $2$   $3d^3$ $3$   $3d^6$ $4$   Comparing the values: For $3d^7$: $\mu = \sqrt{3(3+2)} = \sqrt{15} \ BM \approx 3.87 \ BM$ For $3d^8$: $\mu = \sqrt{2(2+2)} = \sqrt{8} \ BM \approx 2.83 \ BM$ For $3d^3$: $\mu = \sqrt{3(3+2)} = \sqrt{15} \ BM \approx 3.87 \ BM$ For $3d^6$: $\mu = \sqrt{4(4+2)} = \sqrt{24} \ BM \approx 4.90 \ BM$ Thus,the configuration $3d^6$ has the highest number of unpaired electrons $(n=4)$ and consequently the highest magnetic moment.

Which of the following electronic configurations would be associated with the highest magnetic moment?

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