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(A) To determine if two Fischer projections are enantiomers,we assign the $R/S$ configuration to the chiral center in each structure.For structure $I$

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$I$ and $II$

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(A) To determine if two Fischer projections are enantiomers,we assign the $R/S$ configuration to the chiral center in each structure.For structure $I$,the priority order is: $-OH (1) > -CH=CH_2 (2) > -CH_3 (3) > -H (4)$. With $-H$ on a horizontal bond,the clockwise direction corresponds to the $S$ configuration.For structure $II$,the priority order is: $-OH (1) > -CH=CH_2 (2) > -CH_3 (3) > -H (4)$. With $-H$ on a horizontal bond,the counter-clockwise direction corresponds to the $R$ configuration.Since $I$ and $II$ are non-superimposable mirror images of each other,they are enantiomers.Therefore,the correct combination is $I$ and $II$.

Which of the following combinations amongst the four Fischer projections represents the enantiomers?

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