Which of the following is optically active?

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(D) The correct answer is $(D)$. An optically active compound must possess at least one chiral center and lack a plane of symmetry or center of invers

Vedclass · Accepted Answer

Tartaric acid

Vedclass · Answer

(D) The correct answer is $(D)$. An optically active compound must possess at least one chiral center and lack a plane of symmetry or center of inversion. $(A)$ Ethylene glycol $(HO-CH_2-CH_2-OH)$ has no chiral carbon. $(B)$ Oxalic acid $(HOOC-COOH)$ has no chiral carbon. $(C)$ Glycerol $(HO-CH_2-CH(OH)-CH_2-OH)$ has no chiral carbon. $(D)$ Tartaric acid $(HOOC-CH(OH)-CH(OH)-COOH)$ contains two chiral carbon atoms. While the meso-form is optically inactive due to internal compensation,the $d$- and $l$-isomers are optically active. Thus,tartaric acid is the only compound listed that can exhibit optical activity.

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