Find the number of stereoisomers for CH_3-CH( | vedclass

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(C) The given molecule is $CH_3-CH(OH)-CH(OH)-CH_3$,which is $2,3-butanediol$.It has $n = 2$ chiral centers.The molecule is symmetric because the grou

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$3$

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(C) The given molecule is $CH_3-CH(OH)-CH(OH)-CH_3$,which is $2,3-butanediol$.It has $n = 2$ chiral centers.The molecule is symmetric because the groups attached to both chiral centers are identical.For a symmetric molecule with an even number of chiral centers $(n=2)$:Number of optically active isomers $(a)$ = $2^{n-1} = 2^{2-1} = 2^1 = 2$.Number of meso isomers $(m)$ = $2^{(n/2)-1} = 2^{(2/2)-1} = 2^0 = 1$.Total number of stereoisomers = $a + m = 2 + 1 = 3$.

Find the number of stereoisomers for $CH_3-CH(OH)-CH(OH)-CH_3$.

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