Which of the following represents a reverse-b | vedclass

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(B) diode is reverse-biased when the potential at the $P$-terminal $(V_P)$ is lower than the potential at the $N$-terminal $(V_N)$,i.e.,$V_P < V_N$.Ch

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(B) diode is reverse-biased when the potential at the $P$-terminal $(V_P)$ is lower than the potential at the $N$-terminal $(V_N)$,i.e.,$V_P Checking the options:$(A)$ $V_P = 5 	ext{ V}$,$V_N = 0 	ext{ V}$. Since $5 	ext{ V} > 0 	ext{ V}$,it is forward-biased.$(B)$ $V_P = -20 	ext{ V}$,$V_N = -10 	ext{ V}$. Since $-20 	ext{ V} $(C)$ $V_P = 15 	ext{ V}$,$V_N = 10 	ext{ V}$. Since $15 	ext{ V} > 10 	ext{ V}$,it is forward-biased.$(D)$ $V_P = 10 	ext{ V}$,$V_N = -5 	ext{ V}$. Since $10 	ext{ V} > -5 	ext{ V}$,it is forward-biased.Therefore,the correct option is $(B)$.

Which of the following represents a reverse-biased diode?

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