Which is a wrong statement?

  • A
    In $\ln k$ vs $\frac{1}{T}$ plot is a straight line
  • B
    Presence of catalyst will not alter the value of $E_a$
  • C
    Rate constant $k = $ Arrhenius constant $A$: if $E_a = 0$
  • D
    $e^{-E_a / RT}$ gives the fraction of reactant molecules that are activated at the given temp

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Similar Questions

$A$ sample of milk splits after $60 \; min.$ at $300 \; K$ and after $40 \; min.$ at $400 \; K$ when the population of $Lactobacillus \; acidophilus$ in it doubles. The activation energy (in $kJ / mol$) for this process is closest to ............. $kJ / mol$.
(Given: $R = 8.3 \; J \; mol^{-1} \; K^{-1}$,$\ln(1.5) = 0.405$)

$A$ large increase in the rate of a reaction for a rise in temperature is due to:

According to the collision theory of reaction rates:

Which of the following graphs of $\log \, K \rightarrow 1/T$ can be used to calculate the activation energy?

$A \rightarrow B$ (first reaction)
$C \rightarrow D$ (second reaction)
Consider the above two first-order reactions. The rate constant for the first reaction at $500 \ K$ is double of the same at $300 \ K$. At $500 \ K, 50 \%$ of the reaction becomes complete in $2 \ hours$. The activation energy of the second reaction is half of that of the first reaction. If the rate constant at $500 \ K$ of the second reaction is double the rate constant of the first reaction at the same temperature,then the rate constant for the second reaction at $300 \ K$ is . . . . . . $\times 10^{-1} \ hour^{-1}$ (nearest integer).

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