A sample of milk splits after 60 ; min. at 30 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The rate constant $k$ is inversely proportional to the time $t$ required for a specific change (doubling of population),so $k \propto 1/t$.Using t

Vedclass · Accepted Answer

$3.98$

Vedclass · Answer

(D) The rate constant $k$ is inversely proportional to the time $t$ required for a specific change (doubling of population),so $k \propto 1/t$.Using the Arrhenius equation in the form $\ln(k_2 / k_1) = \frac{E_a}{R} [\frac{1}{T_1} - \frac{1}{T_2}]$,we substitute $k_2/k_1 = t_1/t_2$:$\ln(t_1 / t_2) = \frac{E_a}{R} [\frac{1}{T_1} - \frac{1}{T_2}]$$\ln(60 / 40) = \frac{E_a}{8.3} [\frac{1}{300} - \frac{1}{400}]$$\ln(1.5) = \frac{E_a}{8.3} [\frac{400 - 300}{120000}]$$0.405 = \frac{E_a}{8.3} 	imes \frac{100}{120000}$$0.405 = \frac{E_a}{8.3} 	imes \frac{1}{1200}$$E_a = 0.405 	imes 8.3 	imes 1200 = 4033.8 \; J / mol \approx 4.03 \; kJ / mol$.Comparing with the given options,the closest value is $3.98 \; kJ / mol$.

Similar Questions

The reaction rate at a given temperature becomes slower,then

Which of the following graphs between the rate constant $(k)$ and temperature $(T)$ represents the Arrhenius equation?

The rate of a certain biochemical reaction at physiological temperature $T$ occurs $10^{6}$ times faster with an enzyme than without. The change in the activation energy upon adding the enzyme is

Which one of the following is true for an exothermic reaction $A \rightleftharpoons B$,if $E_f$ and $E_b$ are the activation energies of forward and backward reactions respectively?

Define the following terms:
$(1)$ Fraction of molecules
$(2)$ Frequency factor

Vedclass Test Series

Exam Paper Generator

Online Exam Module