Which among the following is the $CORRECT$ formula for the determination of cell constant?

Calculate the degree of dissociation of $0.01 \ M$ acetic acid at $25^{\circ} C$ given that the molar conductivity at concentration $c$ is $\Lambda_{c} = 15.0 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and the limiting molar conductivity is $\Lambda_0 = 300 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.

The cell constant of a cell is $0.5 \ cm^{-1}$ and the resistance $R = 50 \ \Omega$. If the normality is $1 \ N$,then the equivalent conductivity of the electrochemical cell is ...... $\Omega^{-1} \ cm^2 \ (g \ eq)^{-1}$.

The conductivity of a strong electrolyte is:

If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

The molar conductivity of a $0.5 \ mol/dm^3$ solution of $AgNO_3$ with electrolytic conductivity of $5.76 \times 10^{-3} \ S \ cm^{-1}$ at $298 \ K$ is ......... $S \ cm^2/mol$.