If the molar conductivities (in $S \ cm^2 \ mol^{-1}$) of $NaCl$,$KCl$,and $NaOH$ at infinite dilution are $126$,$150$,and $250$,respectively,the molar conductivity of $KOH$ (in $S \ cm^2 \ mol^{-1}$) is

The molar conductance of an infinitely dilute solution of ammonium chloride was found to be $185 \ S \ cm^2 \ mol^{-1}$ and the ionic conductance of hydroxyl and chloride ions are $170$ and $70 \ S \ cm^2 \ mol^{-1}$,respectively. If molar conductance of $0.02 \ M$ solution of ammonium hydroxide is $85.5 \ S \ cm^2 \ mol^{-1}$,its degree of dissociation is given by $x \times 10^{-1}$. The value of $x$ is $...........$ $(Nearest \ integer)$

Kohlrausch's law states that at:

Limiting molar conductivity of $NH_4OH$ [i.e.,$\Lambda ^o_{m(NH_4OH)}$] is equal to:

At $298 \ K$,the equivalent conductance of $0.1 \ M$ acetic acid is $5.20 \ S \ cm^{2} \ eq.^{-1}$. Calculate the degree of dissociation of acetic acid at this concentration in $\%$. Given: $\lambda^{\infty} (H^{+}) = 349.8 \ S \ cm^{2} \ mol^{-1}$ and $\lambda^{\infty} (CH_{3}COO^{-}) = 40.9 \ S \ cm^{2} \ mol^{-1}$.

The molar conductivity of a $0.02 \ M$ solution of an electrolyte is $124 \times 10^{-4} \ S \ m^2 \ mol^{-1}$. What is the resistance of the same solution (in ohms),kept in a cell with a cell constant of $129 \ m^{-1}$?