Calculate the degree of dissociation of $0.01 \ M$ acetic acid at $25^{\circ} C$ given that the molar conductivity at concentration $c$ is $\Lambda_{c} = 15.0 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and the limiting molar conductivity is $\Lambda_0 = 300 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.
- A$0.042$
- B$0.035$
- C$0.025$
- D$0.05$
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$0.5 \ N$ solution of a salt placed between two platinum electrodes $2.0 \ cm$ apart and of area of cross section $4.0 \ cm^2$ has a resistance of $25 \ \Omega$. Calculate the equivalent conductivity of solution ................. $\Omega^{-1} \ cm^2 \ eq^{-1}$
Medium
View SolutionGiven below are two statements:
Assertion $(A)$: Conductivity of an electrolyte decreases on dilution.
Reason $(R)$: On dilution,the number of ions per unit volume increases.
The correct answer is:
Assertion $(A)$: Conductivity of an electrolyte decreases on dilution.
Reason $(R)$: On dilution,the number of ions per unit volume increases.
The correct answer is:
Equivalent conductances of $BaCl_2$,$H_2SO_4$ and $HCl$ at infinite dilution are $\Lambda_1^\infty$,$\Lambda_2^\infty$ and $\Lambda_3^\infty$ respectively. Then,the equivalent conductance of $BaSO_4$ at infinite dilution will be:
Difficult
View SolutionWhich of the following electrolytic solutions has the least specific conductance (in $N$)?
The molar conductivities of $HCl$,$NaCl$,$CH_{3}COOH$,and $CH_{3}COONa$ at infinite dilution follow the order:
DifficultKVPY 2015
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