When will a body of mass $20 \ kg$ moving at $15 \ m s^{-1}$,subjected to a retarding force of $100 \ N$,come to rest (in $s$)?

  • A
    $3$
  • B
    $6$
  • C
    $1.5$
  • D
    $9$

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Similar Questions

$A$ body of mass $5 \ kg$ is moving in a straight line. The relation between its displacement and time is $x = (t^3 - 2t - 10) \ m$. What is the force acting on it at the end of $5 \ s$ (in $N$)?

The magnitude and direction of the acceleration produced in a body of mass $5 \text{ kg}$ when two mutually perpendicular forces $8 \text{ N}$ and $6 \text{ N}$ act on it,are respectively:

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$A$ body of mass $2 \ kg$ moving with velocity of $\overrightarrow{v}_{in} = 3 \hat{i} + 4 \hat{j} \ ms^{-1}$ enters into a constant force field of $6 \ N$ directed along the positive $z$-axis. If the body remains in the field for a period of $\frac{5}{3} \ s$, then the velocity of the body when it emerges from the force field is:

$A$ block of mass $1 \ kg$ starts from rest at $x=0$ and moves along the $X$-axis under the action of a force $F=kt$, where $t$ is time and $k=1 \ Ns^{-1}$. The distance the block will travel in $6 \ seconds$ is: (in $m$)

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