A body of mass 2 kg moving with velocity of | vedclass

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(B) Given: Mass $m = 2 \ kg$, Initial velocity $\overrightarrow{u} = 3 \hat{i} + 4 \hat{j} \ ms^{-1}$, Force $\overrightarrow{F} = 6 \hat{k} \ N$, Tim

Vedclass · Accepted Answer

$3 \hat{i} + 4 \hat{j} + 5 \hat{k}$

Vedclass · Answer

(B) Given: Mass $m = 2 \ kg$, Initial velocity $\overrightarrow{u} = 3 \hat{i} + 4 \hat{j} \ ms^{-1}$, Force $\overrightarrow{F} = 6 \hat{k} \ N$, Time $t = \frac{5}{3} \ s$. Using Newton's second law, the acceleration is $\overrightarrow{a} = \frac{\overrightarrow{F}}{m} = \frac{6 \hat{k}}{2} = 3 \hat{k} \ ms^{-2}$. Using the first equation of motion, $\overrightarrow{v} = \overrightarrow{u} + \overrightarrow{a}t$. Substituting the values: $\overrightarrow{v} = (3 \hat{i} + 4 \hat{j}) + (3 \hat{k}) 	imes \left(\frac{5}{3}ight)$. $\overrightarrow{v} = 3 \hat{i} + 4 \hat{j} + 5 \hat{k} \ ms^{-1}$.

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