When an electron jumps from the orbit n=2 to | vedclass

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Question

(A) The wavelength $\lambda$ of the radiation absorbed when an electron transitions from orbit $n_1$ to $n_2$ is given by the Rydberg formula:$\frac{1

Vedclass · Accepted Answer

$\frac{16}{3 R}$

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(A) The wavelength $\lambda$ of the radiation absorbed when an electron transitions from orbit $n_1$ to $n_2$ is given by the Rydberg formula:$\frac{1}{\lambda} = R \left[ \frac{1}{n_1^2} - \frac{1}{n_2^2} \right]$Given $n_1 = 2$ and $n_2 = 4$:$\frac{1}{\lambda} = R \left[ \frac{1}{2^2} - \frac{1}{4^2} \right]$$\frac{1}{\lambda} = R \left[ \frac{1}{4} - \frac{1}{16} \right]$$\frac{1}{\lambda} = R \left[ \frac{4 - 1}{16} \right]$$\frac{1}{\lambda} = \frac{3 R}{16}$Therefore,the wavelength is $\lambda = \frac{16}{3 R}$.

When an electron jumps from the orbit $n=2$ to $n=4$,the wavelength of the radiation absorbed will be ($R$ is Rydberg's constant).

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