In Bohr's model of the hydrogen atom,let PE r | vedclass

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(B) In Bohr's model,the potential energy of an electron in the $n^{th}$ orbit is given by $PE = -\frac{ke^2}{r_n}$,where $r_n \propto n^2$. As the pri

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$PE$ increases,$TE$ increases

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(B) In Bohr's model,the potential energy of an electron in the $n^{th}$ orbit is given by $PE = -\frac{ke^2}{r_n}$,where $r_n \propto n^2$. As the principal quantum number $n$ increases,the radius $r_n$ increases,making the potential energy $PE$ less negative (i.e.,it increases).The total energy is given by $TE = -\frac{13.6}{n^2} 	ext{ eV}$. As $n$ increases,the denominator $n^2$ increases,making the total energy $TE$ less negative (i.e.,it increases towards zero).Therefore,both $PE$ and $TE$ increase as the electron moves to a higher energy level.

In Bohr's model of the hydrogen atom,let $PE$ represent potential energy and $TE$ represent total energy. When an electron transitions to a higher energy level,

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