When a hemophilic male $(X^h Y)$ marries a carrier female $(X^H X^h)$ for hemophilia,what are the chances of all daughters born being normal (in $\%$)?

  • A
    $75$
  • B
    $0$
  • C
    $100$
  • D
    $50$

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Similar Questions

An example of a disease caused by a molecular mutation is

$A$ woman carrying two genes for haemophilia and one gene for colour blindness on one of her $X$ chromosomes marries a normal man. What will be the phenotype of the progeny?

Match Column-$I$ with Column-$II$ and select the correct option.
Column-$I$ Column-$II$
$(P)$ Haemophilia $(i)$ Recessive gene: $X^{h}X^{h}$
$(Q)$ Colour blindness $(ii)$ Recessive gene: $pp$
$(R)$ Phenylketonuria $(iii)$ Recessive gene: $Hb^{s}Hb^{s}$
$(S)$ Sickle-cell anaemia $(iv)$ Recessive gene: $X^{c}X^{c}$

$A$ colorblind man marries a woman who is the daughter of a colorblind father. What will be the status of their offspring regarding colorblindness?

Describe pedigree analysis and draw its symbols.

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