A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
All sons and daughters haemophillic and colourblind
Haemophillic and colourblind daughters
$50\%$ haemophillic colourblind sons and $50\%$ normal sons
$50\%$ haemophillic daughters and $50\%$ colourblind daughters
:Match the columns :
Column $I$ |
Column $II$ |
$(a)$ Sickle cell anaemia | $(x)$ Homogentisic acid |
$(b)$ Alkaptonuria | $(y)$ Melanin pigmentsare absent |
$(c)$ Albinism | $(z)$ More amount of phenyl alanine |
$(d)$ Phenyl Ketonuria | $(w)$ Defective haemoglobin |
$A$ : The posssibility of a female becoming a haemophilic is extremely rare.
$R$ : Mother of such a female has to be carrier and father should be haemophilic
In the above pedigree, assume that no outsider marrying in, carry a disease. Write the genotypes of $C$ and $D$.