A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be
- [AIPMT 1998]
- A
All sons and daughters haemophillic and colourblind
- B
Haemophillic and colourblind daughters
- C
$50\%$ haemophillic colourblind sons and $50\%$ normal sons
- D
$50\%$ haemophillic daughters and $50\%$ colourblind daughters
Similar Questions
$A$ : Sickel cell anaemia occurs due to the point mutation.
$R$ : $mRNA$ produced from $Hb(s)$ gene has $GAG$ instead of $GUG$.
$A$ : Sickel cell anaemia occurs due to the point mutation.
$R$ : $mRNA$ produced from $Hb(s)$ gene has $GAG$ instead of $GUG$.
If a colour blind woman marries a normal visioned man, their sons will be
If a colour blind woman marries a normal visioned man, their sons will be
- [AIPMT 1999]
Person whose father is colourblind marries a lady whose mother is daughter of a colourblind man. Their children will be
Person whose father is colourblind marries a lady whose mother is daughter of a colourblind man. Their children will be
All sons of a couple are colourblind because
All sons of a couple are colourblind because
What are all the chances of colour blind daughter and sons being born in a marriage of normal man marrying a normal woman, whose father was colour blind
What are all the chances of colour blind daughter and sons being born in a marriage of normal man marrying a normal woman, whose father was colour blind