A woman with two genes for haemophillia and one gene for colourblindness on one of the $X$ chromosomes marries a normal man. How will the progeny be

  • [AIPMT 1998]
  • A

    All sons and daughters haemophillic and colourblind

  • B

    Haemophillic and colourblind daughters

  • C

    $50\%$ haemophillic colourblind sons and $50\%$ normal sons

  • D

    $50\%$ haemophillic daughters and $50\%$ colourblind daughters

Similar Questions

:Match the columns :

Column $I$
 
Column $II$
 
$(a)$ Sickle cell anaemia  $(x)$ Homogentisic acid
$(b)$ Alkaptonuria $(y)$  Melanin pigmentsare absent
$(c)$ Albinism $(z)$  More amount of phenyl alanine
$(d)$ Phenyl Ketonuria $(w)$  Defective haemoglobin

Given below are two statements :
Statement $I :$ Sickle cell anaemia and Haemophilia are autosomal dominant traits.
Statement $II :$ Sickle cell anaemia and Haemophilia are disorders of the blood.
In the light of the above statements, choose the correct answer from the options given below :

  • [NEET 2022]

$A$ : The posssibility of a female becoming a haemophilic is extremely rare.
$R$ : Mother of such a female has to be carrier and father should be haemophilic

In the above pedigree, assume that no outsider marrying in, carry a disease. Write the genotypes of $C$ and $D$.

Female rarely experience the physiologic defect of haemophilia because they do so only when they are